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NeTakaya
2 years ago
14

An interplanetary spacecraft is moving at

Physics
2 answers:
jenyasd209 [6]2 years ago
8 0

Answer:

1,728,000 Km

Explanation:

Relationship of Speed, Distance and Time is

Distance = Speed × time

Given: Speed= 20000 m/s = 20 Km/s

Time =one day = 24 hrs × 60 mins × 60 sec = 86,400 seconds

so Distance = 20 Km/sec × 86,400 sec = 1,728,000 Km

mixer [17]2 years ago
7 0
The awnser is. 1728000 kilometers
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The furnace keeps houseAat 25◦C, while thefurnace in houseBkeeps it at 20◦C. Which house requires heat to be supplied by its fur
EleoNora [17]

Answer:

House A requires heat at a slightest faster rate than B

Explanation:

House A requires heat at a slightest faster rate than B due to the slight high temperature the furnace A is.

5 0
2 years ago
Suppose that a barometer was made using oil with rho=900 kg/m3. What is the height of the barometer at atmospheric pressure?
rewona [7]

Hey there!

The pressure under a liquid column can be , calculated using  the following formula :

P = p x g x h  

P atm = 1.013 x 10⁵ Pa

g = 9.8 m/s²

h = ?

h =  P / ( p x g ) =

h= ( 1.013 x 10⁵ Pa ) / ( 900 x 9.8 ) =

h = ( 1.013 x 10⁵ ) / ( 8820 ) =

h = 11.48 m ≈  11.50 m

Hope this helps!

5 0
2 years ago
If radio waves are used to communicate with an alien spaceship approaching Earth at 10% of the speed of light c, the aliens woul
Brilliant_brown [7]

Answer:

3×10^7 m/s or 0.10c (e)

Explanation: If the actual value of the speed of light were to be put into consideration.

Given that the speed of light is c = 3.0×10^8m/s

The alien spaceship is approaching at the rate of 10% of the speed of light.

10% of 3.0×10^8m/s

10/100 × 3.0×10^8m/s

0.1 ×3.0×10^8m/s

3×10^7 m/s. Which is the same thing as 0.1 of c = 0.1×c

7 0
2 years ago
A bobsled is pushed with a force of 190.08 N. The sled has a mass of 28 kg. What is the acceleration of the bobsled? Report to t
Usimov [2.4K]
By definition it is known that force equals mass by acceleration. In other words F = m * a. To find the acceleration, you must clear the formula mentioned. Therefore, for a force of 190.08N and a mass of 28 Kg, we have that the acceleration is a = F / m = (190.08) / (28) = 6.79 m / s ^ 2
6 0
2 years ago
A rod 150 cm long and of diameter 2.0 cm is subjected to an axial pull of 20 kn. if the modulus of elasticity of the material of
Scilla [17]
Given:
rod of circular cross section is subjected to uniaxial tension.
Length, L=1500 mm
radius, r = 10 mm
E=2*10^5 N/mm^2
Force, F=20 kN = 20,000 N
[note: newton (unit) in abbreviation is written in upper case, as in  N ]

From given above, area of cross section = π r^2 = 100 π =314 mm^2
(i) Stress,
σ
=force/area
= 20000 N / 314 mm^2
= 6366.2 N/mm^2
= 6370 N/mm^2 (to 3 significant figures)

(ii) Strain
ε
= ratio of extension / original length
= σ / E
= 6366.2 /(2*10^5)
= 0.03183 
= 0.0318 (to three significant figures)

(iii) elongation
= ε * L
= 0.03183*1500 mm
= 47.746 mm
= 47.7 mm  (to three significant figures)

5 0
2 years ago
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