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2 years ago

Describe what happens to the particles in a chocolate bar as it melts.

Chemistry

2 answers:

miskamm [114]2 years ago

6 0

The correct answer is D. As the chocolate bar changes from a solid to a liquid the particles move around more.

Explanation:

Changes in the state of a substance (for example from solid to liquid) affect the arrangement and motion of the particles. In this way, in the solid-state particles are organized in a fixed structure and only vibrate; however, as the substance is heated and the state of the substance changes (for example, the chocolate bar is melted) particles gain energy, and this makes them move around more, which causes liquids to have an undefined shape. According to this, in the case of a chocolate bar "As the chocolate bar changes from a solid to a liquid, the particles move around more".

Margarita [4]2 years ago

5 0

Answer:

The correct answer is d. As the chocolate bar changes from a solid to a liquid the particles move around more.

Explanation:

When a chocolate bar melts, it suffers a <u>physical</u> change: a change of state from solid to liquid. In the liquid state, the particles move around more, because they have more kinetic energy (more velocity) and more freedom to move than in solid state. Thus, as the solid became into a liquid, the particles move more.

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2 years ago

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2 years ago

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If the actual yield of the reaction was 75% instead of 100%, how many molecules of no would be present after the reaction was ov

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To be able to answer this equations, we must set given information. Suppose the reaction to yield NO is:

N₂ + O₂ → 2 NO

Next, suppose you have 1 g of each of the reactants. Determine first which is the limiting reactant.

1 g N₂ (1 mol N₂/ 28 g)(2 mol NO/1 mol N₂)= 0.07154 mol NO present

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2 years ago

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kondor19780726 [428]

Explanation:

It is known that 1 gram contains 1000 milligrams. And, mathematically we can represent it as follows.

$\frac{1 g}{1000 mg}$ or $\frac{1000 mg}{1 g}$

So, when we have to convert grams into milligrams then we simply multiply the digit with 1000. And, if we have to convert a digit from milligrams to grams then we simply divide it by 1000.

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2 years ago

Sulfurous acid is a diprotic acid with the following acid-ionization constants: Ka1 = 1.4x10−2, Ka2 = 6.5x10−8 If you have a 1.0

REY [17]

Answer:

pH = 7.1581

Explanation:

The equilibrium of NaHSO₃ with Na₂SO₃ is:

HSO₃⁻ ⇄ SO₃²⁻ + H⁺

<em>Where K of equilibrium is the Ka2: 6.5x10⁻⁸</em>

HSO₃⁺ reacts with NaOH, thus:

HSO₃⁻ + NaOH → SO₃²⁻ + H₂O + Na⁺

As the buffer is of 1.0L, initial moles of HSO₃⁻ and SO₃²⁻ are:

HSO₃⁻: 0.252 moles

SO₃²⁻: 0.139 moles

Based on the reaction of NaOH, moles added of NaOH are subtracting moles of HSO₃⁻ and producing SO₃²⁻. The moles added are:

0.0500L ₓ (1mol /L): 0.050 moles of NaOH.

Thus, final moles of both compounds are:

HSO₃⁻: 0.252 moles - 0.050 moles = 0.202 moles

SO₃²⁻: 0.139 moles + 0.050 moles = 0.189 moles

Using H-H equation for the HSO₃⁻ // SO₃²⁻ buffer:

pH = pka + log [SO₃²⁻] / [HSO₃⁻]

Where pKa is - log Ka = 7.187

Replacing:

pH = 7.187 + log [0.189] / [0.202]

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2 years ago