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Vitek1552 [10]
2 years ago
5

In 1986, a nuclear power accident in Chernobyl, USSR (now Ukraine), led to high radiation levels for miles surrounding the plant

. The high levels of radiation caused elevated mutation rates in the surviving organisms, and evolutionary biologists have been studying rodent populations in the Chernobyl area ever since. Based on your understanding of evolutionary mechanisms, which of the following most likely occurred in the rodent populations following the accident?
Mutation led to increased genetic variation.
Mutation caused genetic drift and decreased fitness.
Mutation caused the fixation of new alleles.
Mutations caused major changes in rodent physiology over time.
Physics
2 answers:
Fittoniya [83]2 years ago
8 0

Answer:

The correct option is A. Mutation led to increased genetic variation.

Explanation:

Mutations are caused when there occurs a change in DNA segments of an organism. Mutations may be natural or due to environmental factors. If the changes are caused in the non-functional DNA then no possible phenotypic effects will be seen. But if mutations occur in the functional DNA, then changes in the genetic, as well as the phenotypic makeup will be seen. These changes will lead to an increase in the genetic variation of the species.

Sliva [168]2 years ago
4 0

Answer:

Option A

Mutation led to increased genetic variation.

Explanation:

From the definition of mutation, it’s a sudden change in the deoxyribonucleic acid (DNA) which tends to alter the genetic message carried by that gene. Mutation is caused by a mutagen where for the case of Chernobyl, USSR (now Ukraine), the mutagen was radiation. Consequently, variations would occur in organisms that inhabited that area. However, it’s important to note that mutation can’t fix new alleles. Neither will mutation cause genetic drift and decreased fitness nor cause changes only in the physiology of an organism as depicted by the other choices. Finally, it’s important to recognize that mutations can increase genetic variation hence option A is the correct answer for this incidence.

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DerKrebs [107]

Answer:

The impact force will be same for both the cases.

Explanation:

The rate of change of momentum is known as the Impulse and is given by:

I = \frac{\Delta p}{\Delta t}

where

I = Impulse

\Delta p = change in momentum

\Delta t = time interval

Now,

In first case both the cars are identical and have same velocity and in the second case, the wall is stationary.

Also, in both the cases the car does not bounces off the things it hit.

Thus

\Delta p = 0 - m\times v = - mv

Thus

Impact force, F = \frac{\Delta p}{\Delta t} = \frac{m\Delta v}{\Delta t}

Therefore, impact force is same for both the cases.

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2 years ago
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klasskru [66]

Answer:

There would be a pressure drop in the direction of the higher opening. This will force air to move in from the lower opening and force it to leave through the higher opening. This will create a convectional movement of air, cooling and ventilating the tunnel.

Explanation:

This is in accordance with bernoulli's law of fluid flow which states that the pressure exerted by a moving fluid is lesser than it would exert if it were at rest.

6 0
2 years ago
Conductance is directly proportional to the length of a conductor. true false user: resistance is inversely proportional to the
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A 20kg mass approaches a spring at a speed of 30 m/s. The mass compresses the spring 12cm before coming to a stop. Calculate the
Oksana_A [137]

Answer:

625000 N/ m

Explanation:

m= 20 kg

v= 30 m/s

x= 12 cm

k = ?

Here when the mass when hits at spring its speed is

Vi= 30 m/s

Finally it comes to rest after compressing for 12 cm

i-e Vf = 0 m/s

Distance= S= 12 cm = 0.12 m

using

2aS= Vf2 - Vi2

==> 2a ×0.12 = o- 30 × 30

==> a = 900 ÷ 0.24 = 3750 m/sec2

Now we know;

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F= -Kx

==> ma= -kx

==> 20 × 3750 = -K × 0.12

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5 0
2 years ago
Last year a baseball player made 63 errors. This year he made 42. What percent decrease was there in the number of errors commit
Crank

Answer:

33.33 %

Explanation:

given,

error last year = 63

error this year = 42

percent decrease in the error = ?

to find the percentage difference in the error formula used is

   = \dfrac{difference}{original}\times 100

   = \dfrac{63-42}{63}\times 100

   = \dfrac{21}{63}\times 100

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Percentage decrease in the number of error is equal to 33.33%.

7 0
2 years ago
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