Question

Last year a baseball player made 63 errors. This year he made 42. What percent decrease was there in the number of errors committed by the baseball player?

Answer 1

Answer:

33.33 %

Explanation:

given,

error last year = 63

error this year = 42

percent decrease in the error = ?

to find the percentage difference in the error formula used is

   = $\dfrac{difference}{original}\times 100$

   = $\dfrac{63-42}{63}\times 100$

   = $\dfrac{21}{63}\times 100$

   = 33.33 %

Percentage decrease in the number of error is equal to 33.33%.