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2 years ago

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Conductance is directly proportional to the length of a conductor. true false user: resistance is inversely proportional to the

_____ area of the conductor. length charge voltage cross-section

2 answers:

zlopas [31]2 years ago

7 0

1) false

2) area of the conductor

aalyn [17]2 years ago

7 0

1.) "False"

2.) Area of Cross-section.

Hope this helps!

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Find an expression for the torsional constant k in terms of the moment of inertia I of the disk and the angular frequency ω of s

sasho [114]

Answer:

Explanation:

The general equation for the disk with moment of inertia I when given small angular displacement $\theta$ is given by

$I\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=-k\theta$

$\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}+\frac{k\theta }{I}=0$

Replacing

$\frac{k\theta }{I}=\omega ^2$

where $\omega$ is the angular frequency of oscillation

General solution for this Equation is given by

$\theta =\theta _{max}\sin \left ( \omega t+\phi \right )$

where $\theta _{max}=maximum\ angular\ displacement$

$\phi =Phase\ difference$

Thus K can be written as

$k=I\omega ^2$

5 0

2 years ago

You are given 6 identical resistors, and allowed to combine them in any possible configuration to produce different equivalent r

tatyana61 [14]

Answer:your gay

Explanation:

gay

7 0

2 years ago

Suppose 1 kg of Hydrogen is converted into Helium. a) What is the mass of the He produced? b) How much energy is released in thi

morpeh [17]

Answer:

a) m = 993 g

b) E = 6.50 × 10¹⁴ J

Explanation:

atomic mass of hydrogen = 1.00794

4 hydrogen atom will make a helium atom = 4 × 1.00794 = 4.03176

we know atomic mass of helium = 4.002602

difference in the atomic mass of helium = 4.03176-4.002602 = 0.029158

fraction of mass lost = $\dfrac{0.029158}{4.03176}$ = 0.00723

loss of mass for 1000 g = 1000 × 0.00723 = 7.23

a) mass of helium produced = 1000-7.23 = 993 g (approx.)

b) energy released in the process

E = m c²

E = 0.00723 × (3× 10⁸)²

E = 6.50 × 10¹⁴ J

4 0

2 years ago

Read 2 more answers

Select examples of simple harmonic motion that can be observed in everyday life.

liberstina [14]

A. a child gently swinging on a swing at small angles all the time

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2 years ago

A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes

OlgaM077 [116]

Answer:

Explanation:

mass of car, m = 1000 kg

initial velocity, u = 20 m/s

final velocity, v = 0 m/s

distance, s = 120 m

Let a be the acceleration of motion

use third equation of motion

v² = u² + 2 as

0 = 20 x 20 + 2 x a x 120

a = - 1.67 m/s²

Let F be the force

Force, F mass x acceleration

F = - 1000 x 1.67

F = - 1666.67 N

The direction of force is towards south and the magnitude of force is 1666.67 N.

8 0

2 years ago