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USPshnik [31]
2 years ago
4

You travel 25 meters east and then travel 48 meters south. What is your total displacement

Physics
1 answer:
Sidana [21]2 years ago
3 0

Answer:

54.1 m at -62.5^{\circ} (south of east)

Explanation:

Displacement is a vector connecting the initial position with the final position of motion.

In this problem, the motion consists of two parts:

- A first movement 25 m east

- A second movement 48 m south

We can therefore write a vector representing the displacement as

d=(25i-48j)

where i is the unit vector indicating the east direction and j the unit vector indicating the north direction.

Therefore, the total displacement is just the magnitude of this vector:

d=\sqrt{25^2+(-48)^2}=54.1 m

And the direction is given by

\theta=tan^{-1}(\frac{d_y}{d_x})=tan^{-1} (\frac{-48}{25})=-62.5^{\circ}

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Explanation:

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2 years ago
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2 years ago
Read 3 more answers
89. An electron is moving in a straight line with a velocity of 4.0×105 m/s. It enters a region 5.0 cm long where it undergoes a
ddd [48]

Explanation:

Given that,

Initial speed of the electron, u=4\times 10^5\ m/s

Distance, s = 5 cm = 0.05 cm

Acceleration of the electron, a=6\times 10^{12}\ m/s^2  

(a) Let v is the electron's velocity when it emerges from this region. It can be calculated as :

v^2=u^2+2as

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v = 871779.788 m/s

or

v=8.71\times 10^5\ m/s

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t=\dfrac{v-u}{a}

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2 years ago
An ocean liner is cruising at 10 meters/second and is about to approach a stationary ferryboat. A parcel is released from the oc
Afina-wow [57]
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First, we determine how long the parcel will fall using:

s = ut + 1/2 at²

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2 years ago
1. Use Coulomb’s Law (equation below) to calculate the approximate force felt by an electron at point A in the schematic below.
Amiraneli [1.4K]

Answer:

Explanation:

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Its direction will be towards Q⁻

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= 27.64 x 10⁻⁶ N/C

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= 44.22 x 10⁻²⁵ N

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2 years ago
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