Question

Consider this molecular‑level representation of a mixture of gases. There are three gas particles containing two spheres. There are six gas particles containing a single sphere of a different color. There are five gas particles containing a single sphere of a third color. If the partial pressure of the diatomic gas is 0.330 atm, what is the total pressure?

Answer 1

Explanation:

The given data is as follows.

        Number of particles of diatomic gas = 3

        Number of particles of monoatomic gas  = 6

       Number of particles of another monoatomic gas  = 5

Therefore, total number of particles or moles present will be as follows.

                      3 + 6 + 5 = 14

As we know that, mole fraction = $\frac{\text{moles of given substance}}{\text{total no. of moles}}$

Hence, more fraction of the diatomic gas will be as follows.

                 mole fraction = $\frac{\text{moles of given substance}}{\text{total no. of moles}}$

                                     = $\frac{3}{14}$

                                     = 0.21

Now, formula to calculate partial pressure will be as follows.

  Partial pressure of one species = molar fraction of that species x total pressure

Therefore,   $P_{diatomic} = \text{mole fraction diatomic} \times P_{total}$

               $P_{total} = \frac{0.330 atm}{0.21}$

                            = 1.57 atm

Thus, we can conclude that total pressure is 1.57 atm.