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sergejj [24]
2 years ago
4

A metal cup full of water has a mass of 1,000 g. The cup itself has a mass of 214.6 g. If the cup has both a diameter and a heig

ht of 10 cm, what is the approximate density of water?
Mathematics
1 answer:
Alex Ar [27]2 years ago
5 0

Answer: Approximate density of water is 1 g/cm³.

Step-by-step explanation:

Since we have given that

Mass of metal cup full of water = 1000 g

Mass of cup = 214.6 g

So, Mass of water = Mass of filled cup - Mass of empty cup

Mass of water = 1000 g - 214.6 g

Mass of water = 785.4 g

Diameter of cup = 10 cm

Radius of cup = 5 cm

Height of cup = 10 cm

So, volume of cup is given by

\pi r^2h\\\\=\dfrac{22}{7}\times 5^2\times 10\\\\=\dfrac{22}{7}\times 250\\\\=785.71\ cm^3

so, Density of water would be

\dfrac{Mass}{Volume}\\\\=\dfrac{785.71}{785.4}\\\\\approx 1\ g/cm^3

Hence, approximate density of water is 1 g/cm³.

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Number of movies —— C

1 —— c= 8
3——- c= 24
5—— c= 40
6 —— c = 40
15—— c = 40
3 0
2 years ago
Two runners are saving money to attend a marathon. The first runner has $112 in savings, received a $45 gift from a friend, and
scoundrel [369]

Answer:

The correct answer is the last option, that is, 112 + 25m + 45 = 50 + 60m

Step-by-step explanation:

We have been given that the first runner has $112 in savings, received a $45 gift from a friend, and will save $25 each month. Therefore, amount of money in the account of first running after m months will be: 112+45+25m

We have been given that the second runner has $50 in savings and will save $60 each month. Therefore, amount of money in the account of second running after m months will be: 50 + 60m

In order for amount of money to be equal in accounts of both the runners, we set up:

112+45+25m=50+60m

Upon rewriting the left hand side using commutative law, we get:

112+25m+45=50+60m

Therefore, we can see that the last option is the correct answer.

7 0
2 years ago
Read 2 more answers
figure PQRS is a parallelogram. What are the measures of angles P and S? ∠P = 20°; ∠S = 160° ∠P = 40°; ∠S = 140° ∠P = 140°; ∠S =
viktelen [127]
I believe it is C (p=140 s=40)
4 0
2 years ago
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The formula that relates the length of a ladder, L, that leans against a wall with distance d from the base of the wall and the
Ulleksa [173]

Answer:

Step-by-step explanation:

The formula that relates the length of a ladder, L, that leans against a wall with distance d from the base of the wall and the height h that the ladder reaches up the wall is L = StartRoot d squared + h squared EndRoot. What height on the wall will a 15-foot ladder reach if it is placed 3.5 feet from the base of a wall?

L = √d² + h²

4 0
1 year ago
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Which system of equations can be used to find the roots of the equation 12 x 3-5x=2 x 2+x+6
kirill [66]

Answer:

Option (a) is correct.

The system of equation becomes

y=12x^3-5x\\\\ y=2x^2+x+6

Step-by-step explanation:

Given : Equation  12x^3-5x=2x^2+x+6

We have to construct a  system of equations that  can be used to find the roots of the equation 12x^3-5x=2x^2+x+6

Consider the given equation 12x^3-5x=2x^2+x+6

To construct a system of equation put both sides of the given equation equal to a same variable.

Let the variable be "y", Then the equation 12x^3-5x=2x^2+x+6

becomes,

12x^3-5x=y=2x^2+x+6

Thus, The system of equation becomes

y=12x^3-5x\\\\ y=2x^2+x+6

Option (a) is correct.

   

8 0
2 years ago
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