If you heat a gas so that collisions are continually bumping electrons to higher energy levels, when the electrons fall back to
1 answer:
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let the length of the beam be "L"
from the diagram
AD = length of beam = L
AC = CD = AD/2 = L/2
BC = AC - AB = (L/2) - 1.10
BD = AD - AB = L - 1.10
m = mass of beam = 20 kg
m₁ = mass of child on left end = 30 kg
m₂ = mass of child on right end = 40 kg
using equilibrium of torque about B
(m₁ g) (AB) = (mg) (BC) + (m₂ g) (BD)
30 (1.10) = (20) ((L/2) - 1.10) + (40) (L - 1.10)
L = 1.98 m
Answer:
<em>a) 17.05 mph</em>
<em>b) 54.7° northeast direction</em>
<em>c) 10.71 mph</em>
<em>The direction is -22.58° relative to the east.</em>
<em></em>
<em>To head northeast, you must either increase your gliding speed or increase your angle relative to the x-axis greater than 45°.</em>
Explanation:
The question is a little confusing but, I guess the correct question should be;
You are flying a hang glider at 14 mph in the northeast direction (45°). The wind is blowing at 4 mph due north.
a) What is your airspeed?
b) What angle (direction) are you flying?
c) The wind increases to 14 mph from north. Now what is your airspeed and what direction are you flying? If your destination is to the northeast, how would you change your speed or direction so you might make it there?
NB: The difference in the question and my suggestion is highlighted boldly.
Your speed = 14 mph
direction is 45° northeast
Th wind speed = 4 mph
direction is north
We resolve the your speed and the wind speed into the horizontal and vertical components
For vertical the component component
= 14(sin 45) + 4 = 9.89 + 4 = 13.89 mph
For the horizontal speed component
= 14(cos 45) + 0 = 9.89 + 0 = 9.89 mph
Resultant speed =
==> = <em>17.05 mph This is your airspeed</em>
b) To get your direction, we use
tan ∅ = /
tan ∅ = 13.89/9.89 = 1.413
∅ = (1.413) = <em>54.7° northeast direction</em>
c) If the wind increases to 14 mph from the north, then it means the wind blows due south. As before, only the vertical component is affected .
In this case,
= 14(sin 45) - 14 = 9.89 - 14 = -4.11 mph
Resultant speed =
==> = <em>10.71 mph This is your airspeed</em>
Your direction will be,
tan ∅ = /
tan ∅ = -4.11/9.89 = -0.416
∅ = (-0.416) =<em> -22.58° this is the angle you'll travel relative to the east.</em>
<em>To head northeast, you must either increase your gliding speed or increase your angle relative to the x-axis greater than 45°.</em>
The force applied by the man is 60 N
Explanation:
We can solve this problem by applying Newton's second law, which states that:
(1)
where
is the net force acting on the child+cart
m is the mass of the child+cart system
a is their acceleration
In this problem, we have:
m = 30.0 kg is the mass
And there are two forces acting on the child+cart system:
- The forward force of pushing, F
- The force resisting the cart motion, R = 15.0 N
Therefore we can write the net force as
where R is negative since its direction is opposite to the motion
So eq.(1) can be rewritten as
And solving for F,
Learn more about Newton's second law:
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