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ycow [4]
2 years ago
10

In Cynthia's physics class, she must turn in four lab reports. For each report, she earns extra credit if her percent error is l

ess than 5%.5%. For her first lab report, she calculated the value of the acceleration due to gravity three times. She got the following three values. 9.56 ms2 9.56 ms2 9.72ms2 9.72ms2 9.88ms2 9.88ms2 The accepted value of the acceleration due to gravity is 9.8ms2.9.8ms2. Which option is closest to Cynthia's percent error? Remember: Take the average of the three measurements before calculating the percent error.
a. about 8%8%.
b. about 1%1%.
c. about 0.8%0.8%.
d. about 5%.
Physics
1 answer:
MariettaO [177]2 years ago
7 0

Answer:

error = 0.82%

Explanation:

The three readings of her gravity calculation is given as

g_1 = 9.56 m/s^2

g_2 = 9.72 m/s^2

g_3 = 9.88 m/s^2

now the mean value of gravity calculation is given as

g_{mean} = \frac{9.56 + 9.72 + 9.88}{3}

g_{mean} = 9.72 m/s^2

now the percentage error in her calculation is given as

error = \frac{9.8 - 9.72}{9.8} \times 100

error = 0.82%

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A ship 1200m off shore fires a gun. how long after the gun is fired will it be heard on the shore?​
ryzh [129]

Answer:

We know that the speed of sound is 343 m/s in air

we are also given the distance of the boat from the shore

From the provided data, we can easily find the time taken by the sound to reach the shore using the second equation of motion

s = ut + 1/2 at²

since the acceleration of sound is 0:

s = ut + 1/2 (0)t²

s = ut    <em>(here, u is the speed of sound , s is the distance travelled and t is the time taken)</em>

Replacing the variables in the equation with the values we know

1200 = 343 * t

t = 1200 / 343

t = 3.5 seconds (approx)

Therefore, the sound of the gun will be heard at the shore, 3.5 seconds after being fired

6 0
2 years ago
A bulldozer does 4,500 J of work to push a mound of soil to the top of a ramp that is 15 m high. The ramp is at an angle of 35°
spin [16.1K]

<em>Answer</em>


Force = 170 N



<em>Explanation</em>

First find the distance (d) travelled by the bulldozer.


Sin 35 = 15/d

d = 15/(sin 35)

= 26.15m


Now;

work done = force × distance.


4500 J = force × 26.15


dividing both sides by 26.15,


Force = 4500/26.15

= 172.07 N


Answer to two significant figures = 170 N

3 0
2 years ago
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Anna drives north at a speed of 50 km/h for the first hour. Then, she drives north for a second hour but slows down to 30 km/h.
8090 [49]

Answer:

The correct answer is A The distance is greater in the first hour because her speed is faster.

Explanation:

During the first hour, Anna is driving at a speed of 50 km/h. During the second hour, she is only driving at a speed of 30 km/h. The faster she goes, the farther she will go.

Hope this helps,

♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥

8 0
2 years ago
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A hockey puck of mass m traveling along the x axis at 4.5 m/s hits another identical hockey puck at rest. If after the collision
TEA [102]

Answer:

D) No, since kinetic energy is not conserved.

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so in Y direction we can say

0 = m(3.5 sin30) - mv_y

v_y = 1.75 m/s

Now similarly in X direction we will have

m(4.5) = m(3.5 cos30 ) + mv_x

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since KE is decreased here so it must be inelastic collision

D) No, since kinetic energy is not conserved.

5 0
2 years ago
Ivan exerts 20 N of force to lift a basket 2 m. He then carries the basket 5 m across a room to place it on a shelf. Ivan does w
amid [387]
A) <span>Ivan does work when he lifts the basket

B) Work = Force * displacement 
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W = 40 Joules

So, The Amount of work he does is 40 Joules

Hope this helps!</span>
7 0
2 years ago
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