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Ierofanga [76]
2 years ago
6

On a trip to the natural history museum you find two minerals that are similar in color. You can see from their chemical formula

s that one mineral contains the elements zinc, carbon, and oxygen. The other mineral contains the elements zinc, silicon, oxygen, and hydrogen. Your friend tells you that the minerals are in the same mineral group. Do you agree? Explain your reasoning.
Chemistry
1 answer:
lianna [129]2 years ago
7 0

Answer:Yes they are in the same mineral group

Explanation:zinc is the central elements there. The rest of the elements are present as impurities due to where it was found. Like carbon is can be found in the soil, silicon with oxygen is basically sand, hydrogen is in the atmosphere and also in water and soil too. So apart from zinc, the rest are normal day to day elements.

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Which element would you expect to form an ionic compound when combined with bromine (Br)?
daser333 [38]
Ionic bond is formed due to the transfer of electrons from one atom to another so that all atoms involved in the bond would become stable (with 8 electrons in the outermost level)

Now, for bromine, it has 35 electrons. This means that bromine has 7 valence electrons in the outermost level. Therefore, bromine needs to gain one electron in order to become stable.

Bromine can react with elements from:
group 1: each element in group 1 needs to lose one electron to become stable. Therefore, one bromine atom can form an ionic bond when combined with an atom of an element from group 1 (element in group 1 loses its electron for bromine atom).
group 2: each element in group 2 needs to lose two electrons to become stable. Therefore, two bromine atoms can form ionic bonds when combined with an atom of an element from group 2 (element in group 2 loses two electrons, one for each bromine atom).
group 3: each element in group 3 needs to lose three electrons to become stable. Therefore, three bromine atoms can form ionic bonds when combined with an atom of an element from group 1 (element in group 3 loses three electrons, one for each bromine atom).

Since no choices are given , I cannot tell the exact choice. But the correct one would be the element from either group 1 , 2 or 3.
3 0
2 years ago
Read 2 more answers
In a certain city, electricity costs $0.17 per kW·h. What is the annual cost for electricity to power a lamp-post for 5.50 hours
Anon25 [30]

Answer:

(a) = $34.123

(b) = $8.532

(c) Additional cost of fluorescent bulb is justified

Explanation:

Cost of electricity = $0.17 per kW·h

(a) For a 100 watt bulb which is the same as 100/1000 or 0.1 kW, the cost per hour =

0.1 × 0.17 = $0.017/h

and for 5.5 hours = 0.017×5.5 = $0.0935

The annual cost, which is 365 days, we have

Annual cost = $0.0935 × 365 = $34.123

(b) For the energy efficient 25-watt bulb, we have

25/1000 = 0.025kW

Power cost per annum =

0.025kW×$0.17 per kW·h×5.5×365 = $8.532

(c) Total cost of incandescent bulb = $0.89 total cost of using the incandescent bulb is $34.123 + $0.89 = $35.02

Total cost of using the energy efficient fluorescent bulb is about $3.49

Total cost of using the energy efficient bulb = $8.532 + $3.49 = $12.02

Total cost of incandescent bulb = $35.02 while total cost of energy efficient bulb is = $12.02

$12.02 <$35.02

Additional cost of fluorescent bulb is justified

8 0
2 years ago
Calculate the rate of emission of SO2 in g/s that results in a centerline (y = 0) concentration at ground level of 1.786 x 10-3
mr_godi [17]

Answer:

790 g/s

Explanation:

The first thing to do is to make sure to calculate the standard deviation of the y-axis and the z-axis and the values for both axis are; 215 m and 450 m for y-axis and z-axis respectively.

The next thing to do now is to find the rate of emission of SO2 in units of g/s using the relation by using the formula below;

Emission rate of pollutant, E = (x × π × by × bz × g) ÷ [ e^(-1/2) × (y/by)^2] × [e^(-1/2)× (h/bz)^2].

Where g = wind direction, y and h are the distance in metres.

Therefore, slotting in the values into the Emission rate of pollutant equation above, we have;

Emission rate of pollutant,E =[ 1.412 × 10^-3] × π × 215 × 450 × 1.8] ÷ [e^(-1/2)(0/215)^2] × e^ (-1/2)(94/450)^2.

Emission rate of pollutant,E = 790 g/s.

6 0
2 years ago
A cylindrical glass bottle 21.5 cm in length is filled with cooking oil of density 0.953 g/mL. If the mass of the oil needed to
jeka57 [31]

Answer:inner Diameter =9.19cm

Explanation:

Density is calculated as Mass/ Volume

therefore

Volume= Mass/ Density = 1360g/ 0.953g/ml=1,427 ml

1ml = 1cm³

1,427ml = 1,427cm³

Also We know that Volume of a cylinder = πr²h or  πr²l

1,427cm³ = 3.142 x r² x 21.5 cm

 r² =  1,427cm³/ (3.142 x 21.5cm)

r² =21.124cm²

\sqrt{21.124}= r²

r= 4.596cm

Diameter=  2 x radius

=2 x 4.596

=9.19cm

7 0
2 years ago
A solution was prepared by dissolving 200.0 g of KCI in 215 g of water.
Archy [21]

Answer:mole fraction of KCl = 0.18

Explanation:

no of moles of KCl     = Mass/Molar mass

where mass (weight) of KCl = 200.0g

molar mass of KC1= 74.6g/mol

                                                = 200/74.6   = 2.68 moles

no of moles of H2O = Mass/Molar mass

where mass (weight) of water = 215.0g

molar mass of water = 18.0g/mol

                                              = 215/18   = 11.94moles

mole fraction of KCl  = no of moles of KCl/(no of moles KCl + no of moles of H2O(water))

                                                = 2.68/(2.68+ 11.94)

                                                 = 2.68/14.62   = 0.18

5 0
2 years ago
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