First, you must find an equation. You would first find the length of 1 square, and then multiply it by how many rows. Then on the side, you would find the width on one square, and then multiply it by how many columns. Once you find you total length and width, find the perimeter of the whole quilt! Let me know if there is any questions! <span />
Answer:20
Step-by-step explanation:14+6=20
20-6=14
Answer:
The correct options are 1 and 3.
Step-by-step explanation:
From the given box plot it is clear that


Q₁ is 25% of a data.

Median is 50% of a data.

Q₃ is 75% of a data.

34 is minimum value of the data and 46 is median it means 50% of the data values lies between 34 and 46. Therefore option 1 is correct.
42 is first quartile and and 70 is third quartile. it means 50% of the data values lies between 42 and 70. Therefore option 2 is incorrect.
The difference between Minimum value and first quartile, Maximum value and third quartile is less than 1.5×(IQR), therefore it is unlikely to have any outliers in the data.
Hence option 3 is correct.
The interquartile range of the data is


The interquartile range is 28. Therefore option 4 is incorrect.
Range of the data is


The range is 42. Therefore option 5 is incorrect.
First let's write out the inequality before choosing a graph.
x apples each weighing 1/3 of a pound: 1/3x
y pounds of grapes: y
So...
1/3x + y < 5
The maximum weight is 4 pounds since the total weight of both the grapes and apples are less than 5.
In the y-axis, the first, third, and fourth graphs already exceed the capacity of 5 pounds.
So, by process of elimination, the correct graph for this problem is the second one.
Year Sam Sally1: X (3/2)X-10002: (5/2)X-2000 2X-15003: X/5+1000 X/4+1400Total 37X/10-1000 15X/4-1100
Since their investments are known to be equal, we equate the two totals and solve for X.37X/10-1000=15X/4-1100(150-148)X/40 = 1100-1000X/20=100X=2000
So Sam invested $2000 the first year.Sally invested X/4+1400=1900 in the last year.