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telo118 [61]
2 years ago
13

A maths class has equal numbers of boys and girls. Eight of the girls left early to play in a netball match. This left 3 times a

s many boys in the class as girls. How many students are in the class?
Mathematics
1 answer:
irina [24]2 years ago
4 0

Step-by-step explanation:

x = boys / y = girls / s = total number of students

x + y = s

3x + y - 8 = s

Maybe someone can improve upon this because this is all I know. Not the answer btw ^^^

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A sewing club is making a quilt consisting of 25 squares with each side of the square measuring 30 centimeters. If the quilt has
Sedbober [7]
First, you must find an equation. You would first find the length of 1 square, and then multiply it by how many rows. Then on the side, you would find the width on one square, and then multiply it by how many columns. Once you find you total length and width, find the perimeter of the whole quilt! Let me know if there is any questions! <span />
5 0
2 years ago
The sum of Claudia's age and Pedro's age is
Drupady [299]

Answer:20

Step-by-step explanation:14+6=20

20-6=14

6 0
2 years ago
Which statements about the box plot are correct? Check all that apply.
Rudiy27

Answer:

The correct options are 1 and 3.

Step-by-step explanation:

From the given box plot it is clear that

\text{Minimum values}=34

Q_1=42

Q₁ is 25% of a data.

Median=46

Median is 50% of a data.

Q_3=70

Q₃ is 75% of a data.

\text{Maximum values}=76

34 is minimum value of the data and 46 is median it means 50% of the data values lies between 34 and 46. Therefore option 1 is correct.

42 is first quartile and and 70 is third quartile. it means 50% of the data values lies between 42 and 70. Therefore option 2 is incorrect.

The difference between Minimum value and first quartile, Maximum value and third quartile is less than 1.5×(IQR), therefore it is unlikely to have any outliers in the data.

Hence option 3 is correct.

The interquartile range of the data is

IQR=Q_3-Q_1

IQR=70-42=28

The interquartile range is 28. Therefore option 4 is incorrect.

Range of the data is

Range=Maximum-Minimum

Range=76-34=42

The range is 42. Therefore option 5 is incorrect.

3 0
2 years ago
Read 2 more answers
A grocery bag contains x apples, each weighing of a pound, and y pounds of grapes. The total weight of the grocery bag is less t
kupik [55]
First let's write out the inequality before choosing a graph.

x apples each weighing 1/3 of a pound: 1/3x

y pounds of grapes: y

So...

1/3x + y < 5

The maximum weight is 4 pounds since the total weight of both the grapes and apples are less than 5.

In the y-axis, the first, third, and fourth graphs already exceed the capacity of 5 pounds.

So, by process of elimination, the correct graph for this problem is the second one.
4 0
2 years ago
Read 2 more answers
For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second
nikitadnepr [17]
Year         Sam              Sally1:             X                    (3/2)X-10002:            (5/2)X-2000     2X-15003:             X/5+1000       X/4+1400Total         37X/10-1000    15X/4-1100
Since their investments are known to be equal, we equate the two totals and solve for X.37X/10-1000=15X/4-1100(150-148)X/40 = 1100-1000X/20=100X=2000
So Sam invested $2000 the first year.Sally invested X/4+1400=1900 in the last year.
6 0
2 years ago
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