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Contact [7]
2 years ago
10

Two atoms collide while moving in a dilute gas. The larger atom has a mass M1 = 6 Daltons and a speed v1 = 200 m/s, while the sm

aller has a mass M2 = 1 Daltons. During the collision both atoms simply bounce off each other. They do not change their speeds, but after the collision they each change their directions, bouncing in the indicated directions. (You may express your results using the mass unit "Daltons". 1 Dalton is approximately equal to the mass of a proton or neutron and is defined as one-twelfth the mass of a single neutral carbon-12 atom in its ground state.)
A. What is the magnitude of the change in the momentum, Δp1, of mass M1?
B. What is the change in the total momentum of the pair?
C. What is the magnitude of the change in the momentum Δp2, of mass M2?
Physics
1 answer:
olga2289 [7]2 years ago
8 0

Answer:

a). ΔP1=-2.4 x10^{3}  \frac{D*m}{s}

b). Pp=0 F=0

c). ΔP2=2.4 x10^{3}  \frac{D*m}{s}

Explanation:

Initial momentum

P_{1}=m_{1}*v_{i1}

Final momentum

P_{1f}=m_{1}*v_{f1}=-m_{1}*v_{i1}

The change of momentum m1 is:

a).

ΔP1=P_{1f}-P_{1}

ΔP1=-m_{1}*v_{i1}-m_{1}*v_{i1}

ΔP1=-2*m_{1}*v_{i1}

ΔP1=-2*6 D*200\frac{m}{s}

ΔP1=-2.4x10^{3}\frac{D*m}{s}

b).

The law of conservation of energy in this case there is not external forces so the momentum of the pair change is equal to zero

P=0

Fx=0

c).

ΔP1+ΔP2=0

ΔP2=-ΔP1

ΔP2=--2.4x10^{3}\frac{D*m}{s}

ΔP2=2.4x10^{3}\frac{D*m}{s}

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120V

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Think of something from everyday life that follows a two-dimensional path. It could be a kicked football, a bus that's turning a
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What is the tangential velocity at the edge of a disk of radius 10cm when it spins with a frequency of 10Hz? Give your answer wi
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Answer:

630cm/s

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In simple harmonic motion, the tangential velocity is expressed mathematically as v = ὦr

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Given the radius of disk = 10cm

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Given the indices of refraction n1 and n2 of material 1 and material 2, respectively, rank these scenarios on the basis of the p
lisov135 [29]

Answer:

c>d>f=a>b>e

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When a pair of medial has greater difference between the their individual refractive indices with respect to vacuum then it has a greater deviation between the refracted ray and the incident ray.

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\rm refractive\ index\ (n)=\frac{speed\ of\ light\ in\ the\ incident\ medium}{speed\ of\ light\ in\ the\ refracted\ medium}

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f)

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