4-6. Simplify the expressions below. Homework Help ✎ a. 8 − 13 − (−4) b. 4 − (−7) + (−2) c. −7 + 3 − 20 4-7. Copy each expressio
n and simplify it. Show all of your steps. Homework Help ✎ a. 1.234 + 0.58 + 5.316 b. 6.1 − 1.536 c. 4.8(0.6) 4-8. Tina's rectangular living-room floor measures 15 feet by 18 feet. Homework Help ✎ a. How many square feet of carpet will Tina need to cover the entire floor? b. The carpet Tina likes is sold by the square yard. How many square yards will she need? (1 yard = 3 feet)
1 answer:
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Let m∠CLN = x. Then m∠ALM = 3x, and m∠A = 90°-x, m∠C = 90°-3x.
The sum of angles of ∆ABC is 180°, so we have
... 180° = 40° + m∠A + m∠C
Using the above expressions for m∠A and m∠C, we can write ...
... 180° = 40° + (90° -x) + (90° -3x)
... 4x = 40° . . . . . . . . . add 4x-180°
... x = 10°
From which we conclude ...
... m∠C = 90°-3x = 90° - 3·10° = 60°
The ratio of CN to CL is
... CN/CL = cos(∠C) = cos(60°)
... CN/CL = 1/2
so ...
... CN = (1/2)CL
Its not possible because if you try to multiply back and forth it wont work.
Answer:
Approximately, 159 men weighs more than 165 pounds and 159 men weighs less than 135 pounds.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 150 pounds
Standard Deviation, σ = 15
We are given that the distribution of weights of 1000 men is a bell shaped distribution that is a normal distribution.
Formula:
P( men weighing more than 165 pounds)
P(x > 165)
Calculation the value from standard normal z table, we have,
Approximately, 159 men weighs more than 165 pounds.
P(men weighing less than 135 pounds)
P(x < 135)
Calculation the value from standard normal z table, we have,
Approximately, 159 men weighs less than 135 pounds.