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Sidana [21]
2 years ago
11

Julian and Joshua each maintain a constant speed as they run laps around a 400-meter track. In the time it takes Julian to compl

ete two laps, Joshua completes three laps. Julian runs each mile in 12 minutes. How many minutes does it take Joshua to run exactly one mile?

Physics
2 answers:
crimeas [40]2 years ago
8 0

Answer:

8

Explanation:

Marysya12 [62]2 years ago
5 0

Answer:

the time Joshua travels 1 mile is 12.5 min

Explanation:

Let's start by finding the distance traveled on each lap,

Let's reduce everything to the SI system

    R = 400 m

    d = 1 mile (1609 m / 1 mile) = 1609 m

    L = 2 pi R

    L = 2 pi 400

    L = 2513 m

Let us form a rule of proportions if 2 turns of Julian is 3 turns Joshua, for 1 turn of Joshua how many turns Julian took

    lap Julian = 2/3 turn Joshua

Let's calculate what distance is the same for both of them since they are on the same track

    1 lap = 2513 m

    d. Julian = 2/3 2513 m

    d Julian = 1675 m distance Joshua

Let us form the last rule of three or proportions if 1609 m you travel in 12 min how long it takes to travel 1675 m

    t Julian = 1675/1609 12

    t = 12.5 s

Since this is the distance Joshua travels, this is the time Joshua travels 1 mile

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the distance between the sun and earth is about 1.5X10^11 m. express this distance with an SI prefix and kilometers
Angelina_Jolie [31]
First, we write the SI prefixed. The SI unit for distance is meters.

Kilo = 10³
Mega = 10⁶
Giga = 10⁹
Terra = 10¹²

Because our value has ten to the power of 11, we will use the closest and lowest power prefix, which is giga. 

1.5 x 10¹¹ /  10⁹
= 1.5 x 10² Gm or 150 Gm

Writing in kilometers, we simply repeat the procedure except we divide by 10³ this time.

1.5 x 10¹¹ / 10³
= 1.5 x 10⁸ km
5 0
2 years ago
(8%) Problem 9: Helium is a very important element for both industrial and research applications. In its gas form it can be used
exis [7]

Answer:

2046.37 kPa

Explanation:

Given:

Number of moles, n = 125

Temperature, T = 20° C = 20 + 273 = 293 K

Radius of the cylinder, r = 17 cm = 0.17 m

Height of the cylinder, h = 1.64 m

thus,

volume of the cylinder, V = πr²h

= π × 0.17² × 1.64

= 0.148 m³

Now,

From the ideal gas law

we have

PV = nRT

here,

P is the pressure

R is the ideal gas constant = 8.314  J / mol. K

thus,

P × 0.148 = 125 × 8.314 × 293

or

P × 0.148 = 304500.25

or

P = 2046372.64 Pa = 2046.37 kPa

6 0
2 years ago
Consider a loop of wire placed in a uniform magnetic field. Which factors affect the magnetic flux Φm through the loop?
dimaraw [331]

Answer:

* The value of the magnetic field changes either in time or space

* The waxed area changes, the bow is fitting in size

* The angle between the field and the area changes

Explanation:

Magnetic flux is the scalar product of the magnetic field over the area

               Ф = ∫ B. dA

where B is the magnetic field and A is the area

Let's look at stationary, for which factors affect flow

* The value of the magnetic field changes either in time or space

* The waxed area changes, the bow is fitting in size

* The angle between the field and the area changes

4 0
2 years ago
The diagram shows the electric field due to point charge Q. Which statements are correct? Check all that apply.
Bess [88]

Answer:

The <em>correct</em> statements  are:

  • <em>A. The electric field is nonuniform.</em>
  • <em>D. Charge Q is positive.</em>
  • <em>E. If charge A moves toward charge Q, it must be a negative charge</em>

Explanation:

The answer choices are:

  • A. The electric field is nonuniform.
  • B. The electric field is uniform.
  • C. Charge Q is negative.
  • D. Charge Q is positive.
  • E. If charge A moves toward charge Q, it must be a negative charge.
  • F. If charge A moves toward charge Q, it must be a positive charge.

<h2>Solution</h2>

The <em>electric field</em> is the electrostatic force per unit of charge,  

         \vec E=\dfrac{\vec F}{Q}

around around a charge, where another charge would experience the electrostatic force.

The electric field lines are shown in a diagram with arrows ditributed radially away from a positive charge and radially toward a negative charge.

Since the arrows are away from Q, Q is a positive charge: <em>statement D.</em>

Since the size of the arrows decreases as you move away  from Q the stregth of the field is not uniform: <em>statement A.</em>

Since the charge Q is positive, a negative charge would be attracted toward it: <em>statement E.</em>

4 0
2 years ago
Derive an algebraic expression for the tension in the segment of the cord between the post and block A (assumed massless). Expre
lubasha [3.4K]
T=m1a+m2a 

a=v^2/r v=r*w w=2πF--->a=r(2f)^2 <r1 for m1 and r2 for m2> 

T=(m1r1+m2r2)(2πf)^2 <i factored out (2πf)^2 
3 0
2 years ago
Read 2 more answers
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