<span>Avogadro's number
represents the number of units in one mole of any substance. This has the value
of 6.022 x 10^23 units / mole. This number can be used to convert the number of
atoms or molecules into number of moles. We calculate as follows:
</span>1.40x10^23 molecules of N2 ( 1 mol / 6.022 x 10^23 molecules ) ( 28.02 g / mol ) = 6.51 g N2
Answer:
mass = 58.944 g
Explanation:
Given data:
Number of moles of SO₂ = 0.921 mol
Mass of SO₂ = ?
Solution:
Formula:
Number of moles = mass/ molar mass
First of all we will calculate the molar mass.
SO₂ = 32 + 16×2 = 64 g/mol
Now we will put the values in formula.
Number of moles = mass/ molar mass
0.921 mol = mass /64 g/mol
mass = 0.921 mol × 64 g/mol
mass = 58.944 g
The question is missing the graphics required to answer which I have attached as an image.
There are four different representations of the orientation of water molecules around chloride anion. Let's first analyze the water molecule.
We have H-O-H as the structure of water. The oxygen atom is more electronegative than the hydrogen atoms, which results in a partial positive charge on the hydrogen atoms and a partial negative charge on the oxygen atom.
The chloride anion is a negative charge. Therefore, the water molecules should orient themselves with the hydrogen atoms facing the chlorine atom as the partial positive charge on the hydrogen atoms will be attracted to the negative charge of the chlorine atom.
The correct representation is shown in graph 3 which shows all hydrogen atoms facing the chlorine anion.
Answer:
Sodium will an electron and chlorine will gain an electron
Explanation:
The electronic configurations of sodium and chlorine are;
Sodium- 1s2 2s2 2p6 3s1
Chlorine- 1s2 2s2 2p6 3s2 3p5
Hence, sodium can easily loose one electron to chlorine to attain a noble gas configuration while chlorine accepts one electron to attain the noble gas configuration.
From Charle's law the volume of a fixed mass of a gas is directly proportional to the absolute temperature at constant pressure.
Therefore';
V1/T1=V2/T2
Where; V1 = 2.40 l, T1 = 273 +20= 293 K, V2 = 4.80, and T2= ?
2.4/293= 4.8/T2
T2= (4.8×293)/2.4
= 586 K or 313° C