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2 years ago

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In case 1, one end of a horizontal plank of mass M and length L is attached to a wall by a hinge and the other end is held up by

a wire attached to the wall. In case 2 the plank is half the length but has the same mass as in case 1, and the wire makes the same angle with the plank. 1) In which case is the tension in the wire biggest?

1 answer:

Goryan [66]2 years ago

5 0

Answer:

Same.

Explanation:

I made a diagram with the description that is given. So things to be able to perform. In this diagram I consider the recessed bar.

For the solution to this problem it is necessary to take into account the concepts of static force and torque.

For case 1,

We perform sum of moments in the embedded end,

$\sum T = 0$

$F(L)(sin\theta) -mg (\frac{L}{2})=0$

clearing F,

$F=\frac{mg}{2sin\theta}$

For case 2,

We perform sum of moments in the embedded end

$F(\frac{L}{2})sin\theta - mg \frac{L/2}{2}=0$

$F\frac{L}{2}sin\theta = mg \frac{L}{4}$

$F = \frac{mg}{2sin\theta}$

<em>We can verify that the tension for both cases is</em><em> same</em><em>.</em>

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A conducting sphere of radius 5.0 cm carries a net charge of 7.5 µC. What is the surface charge density on the sphere?

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Answer:

$\sigma=0.014\ C/m^2$

Explanation:

Given that,

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So, the surface charge density on the sphere is $0.014\ C/m^2$ .

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2 years ago

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To solve this problem we will use the kinematic equations of angular motion in relation to those of linear / tangential motion.

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Our data is given as:

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$a_c = \frac{v^2}{r}$

$a_c = \frac{(r\omega)^2}{r}$

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2 years ago

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Answer:

Explanation:

Analysis of structure gives

a=gsinθ−μkgcosθ

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