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2 years ago

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Filip, a finance executive, loves playing with numbers and hates sports. His manager, Daphne, asks him to represent their compan

y in an upcoming corporate tennis match. He agrees to participate because he wants to impress Daphne and increase his chances of being promoted and receiving a big raise in his salary. In this scenario, Filip is driven by

1 answer:

Alex17521 [72]2 years ago

7 0

D. extrinsic motivation

Explanation:

From the statement of events leading to his participation in the tennis match, one can deduce that Filip is driven by extrinsic motivation.

What is extrinsic motivation?

it is a motivation driven by external rewards.
Some of the rewards can be grades, promotion, money, car e.t.c

Here one can observed that the reason Filip wants to be a part of the tennis match is to be promoted and receive a big raise in salary from his superior.

Learn more:

Reinforcement brainly.com/question/7064336

#learnwithBrainly

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An astronaut holds a rock 100m above the surface of Planet XX. The rock is then thrown upward with a speed of 15m/s, as shown in

mixer [17]

Answer:

Explanation:

Using the equation of motion to get the acceleration due to gravoty of the rock on the planet.

S = ut+ 1/2at² where;

S is the distance of the rock above the surface of the planet = 100m

u is the initial velocity = 15m/s

a is the acceleration due to gravity

t is the time taken by the rock to reach the ground = 10s

Since the rock is thrown upward the acceleration due to gravity will be negative i.e a= -g

The equation becomes S = ut- 1/2gt²

Substituting the given value to get the time t

100 = 15(10)- 1/2g(10)²

100 = 150-50g

100-150 = -50g

-50 = -50g

g = -50/-50

g = 1m/s²

<em>Hence the acceleration due to gravity of the rock when it is on Planet XX is 1m/s²</em>

8 0

2 years ago

A 120-g block of copper is taken from a kiln and quickly placed into a beaker of negligible heat capacity containing 300 g of wa

gavmur [86]

Answer : The correct option is, (d) $535^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of copper = $0.10cal/g^oC$

$c_2$ = specific heat of water = $1.00cal/g^oC$

$m_1$ = mass of copper = 120 g

$m_2$ = mass of water = 300 g

$T_f$ = final temperature of mixture = $35^oC$

$T_1$ = initial temperature of copper = ?

$T_2$ = initial temperature of water = $15^oC$

Now put all the given values in the above formula, we get:

$120g\times 0.10cal/g^oC\times (35-T_1)^oC=-300g\times 1.00cal/g^oC\times (35-15)^oC$

$T_1=535^oC$

Therefore, the temperature of the kiln was, $535^oC$

7 0

2 years ago

Read 2 more answers

A 1200 kg car reaches the top of a 100 m high hill at A with a speed vA. What is the value of vA that will allow the car to coas

SVEN [57.7K]

Answer:

the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 is 31.3 m/s

Explanation:

given information

car's mass, m = 1200 kg

$h_{A}$ = 100 m

$v_{A}$ = $v_{A}$

$h_{B}$ = 150 m

$v_{B}$ = 0

according to conservative energy

the distance from point A to B, h = 150 m - 100 m = 50 m

the initial speed $v_{A}$

final speed $v_{B}$ = 0

thus,

$v_{B}$ ² = $v_{A}$ ² - 2 g h

0 = $v_{A}$ ² - 2 g h

$v_{A}$ ² = 2 g h

$v_{A}$ = √2 g h

= √2 (9.8) (50)

= 31.3 m/s

8 0

2 years ago

A crane uses a block and tackle to lift a 2200N flagstone to a height of 25m

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Remember the headline: ENERGY IS NEVER CREATED OR DESTROYED

The amount of energy before and after are always equal. All we ever do with energy is move it around from one place to another.

a). A crane can't create energy. Lifting the same rock in 20 different ways always takes the <u><em>same amount of work</em></u>. It doesn't matter whether one person picks the rock straight up, or 50 people get around it and lift it, or roll it up a ramp, or lift it with 16 pulleys and a mile of rope, or use a giant steam crane.

You want to lift a 2200N weight up 25m, you're going to have to supply

(2200N) x (25m) = <em>55,000 Joules</em> of work.

c). YOU put out 55,000 Joules of energy. It had to GO someplace. Where is it now ? ===> It's the potential energy the rock has now, from being 25m higher than it was before. That <em>55,000 Joules</em> is NOW the potential energy of the rock.

No energy was created or destroyed. It just got moved around.

55,000 Joules of energy began as nuclear energy in the core of the sun. Solar radiation carried it to the Earth. Plants absorbed it, and stored it as chemical energy. You ... or a cow that you ate later ... ate the plants and took the chemical energy. One way or the other, the chemical energy got stored in your blood and fat. When you needed to put it out somewhere, you moved it into your muscles, and they converted it into mechanical energy. Then you used the mechanical energy to exert forces. Today, you used the original 55,000 joules to lift the flagstone, and NOW that energy is in the flagstone, 25 meters up off the ground !

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2 years ago

The hammer throw was one of the earliest Olympic events. In this event, a heavy ball attached to a chain is swung several times

Aleonysh [2.5K]

Answer:

Given that

T= 0.43 s

Radius of the ball path's , r=2.1 m

a)

We know that

f= 1/T

Here f= frequency

T= Time period

Now by putting the values

f= 1/T

T= 0.43 s

f= 1/0.43

f=2.32 Hz

b)

We know that

V= ω r

ω = 2 π f

ω=Angular speed

V= Linear speed

ω = 2 π f=ω = 2 x π x 2.32 =14.60 rad/s

V= ω r= 14.60 x 2.1 = 30.66 m/s

c)

Acceleration ,a

a =ω ² r

a= 14.6 ² x 2.1 = 447.63 m/s²

We know that g = 10 m/s²

So

a= a/g= 447.63/10 = 44.7 g m/s²

a= 44.7 g m/s²

7 0

2 years ago