Answer:
Ok:
Explanation:
So, you can use the Henderson-Hasselbalch equation for this:
pH = pKa + log(
) where A- is the conjugate base of the acid. In other words, A- is the deprotonated form and HA is the protonated.
We can solve that
1 = log(
) and so 10 = or 10HA = A-. For every 1 protonated form of adenosine (HA), there are 10 A-. So, the percent in the protonated form will be 1(1+10) or 1/11 which is close to 9 percent.
<u>Answer:</u>
Specific heat of a substance is the value that describe how the added heat energy of substance has the impact on its temperature.
Unit is <em>
</em>
<em>C = Q/m. ∆T</em>
<em>C – Specific heat </em>
<em>Q- heat energy (J)</em>
<em>M – Mass (Kg)</em>
<em>∆T- change in temperature (K) </em>
<u>Explanation:</u>
<em>Given data:</em>
<em>M= 140 g = 0.14 Kg</em>
<em>Q – 1080 Joules.</em>
<em>∆T – 98.4 – 62.2 = 36.2</em>
Substituting the given data in Equation
<em>Specific heat of Aluminium = 
</em>
Answer:
The kinetic increases by 48.84 %
Explanation:
The expression for the kinetic energy is:-
Where, m is the mass of the object
v is the velocity of the object
Let the new velocity is:- v'
v is increased by 22 %. Thus, v' = 1.22 v
So, the new kinetic energy is:-
<u>Thus, the kinetic increases by 48.84 %</u>
It's a cube so the volume = edge^3
Volume = 2.5^3 cm^3 = 15.625 cm^3
density = mass / volume = 42.20 / 15.625 = 2.70 You have 3 places of accuracy.
density of object = 2.70 grams / cm^3 <<<<=== answer.
C) change to water at the same temperature
Explanation:
Adding 334Joules of heat to one gram of ice at STP will cause ice to change to water at the same temperature.
- The heat of fusion is the amount of energy needed to melt a given mass of a solid
- It is also conversely the amount of energy removed from a substance to freeze it.
- The addition of this energy does not cause a decrease or increase in temperature.
- Only a phase change occurs.
Learn more:
Heat of fusion brainly.com/question/4050938
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