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2 years ago

After Larry had taken Nexium for 4 weeks, the pH in his stomach was raised to 4.52. What is the [H3O+] in his stomach?

Chemistry

2 answers:

Neporo4naja [7]2 years ago

7 0

Answer:

The [H3O+] in his stomach is 3,02x10-5 M. See the explanation below, please.

Explanation:

We use the formula:

pH= -log (H30+)

(H30+)= antilog - (pH) =antilog - (4,52) = 3,02e-5 M

GalinKa [24]2 years ago

4 0

$\mathrm{H}_{3} \mathrm{O}^{+} \text {in stomach }=\frac{3.0 \times 10^{-5} \mathrm{M}}{ }$

Explanation:

Nexium (Generic name: Esomeprazole Magnesium) basically used to treat stomach acid problems, by decreasing amount of acid secretion and Increasing pH needed for body.

$\mathrm{H}_{3} \mathrm{O}^{+}$ in stomach is gastric acid formed by following reaction

$\mathbf{H C l}+\mathbf{H}_{2} \mathbf{O} \longrightarrow \mathbf{H}_{3} \mathbf{O}^{+}+\mathbf{C l}^{-}$

The $p H$ of a solution can be found by using formula:

$-\log \left[\mathbf{H}_{3} \mathbf{O}^{+}\right]=p H$

So here $p H$ in Larry’s stomach = 4.52

From above formula hydronium ion concentration is

$\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=10^{-p H}=10^{-4.52}=3.0 \times 10^{-5} \mathrm{M}$

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2 years ago

The Michaelis-Menten equation is an expression of the relationship between the initial velocity,V0, of an enzymatic reaction and

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Answer:

Option 2, Half of the active sites are occupied by substrate

Explanation:

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$V_0=\frac{V_{max\ [S]}}{k_M+[S]}$

Here, $K_m$ is Michaelis-Menten constant and [S] is substrate concentration.

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3 years ago

1. A chemist prepares hydrogen fluoride by means of the following reaction:

Natasha_Volkova [10]

Answer:

a) Theoretical Yield of HF = 5.64 grams

b) Percentage Yield = 39%

Explanation:

Reaction Given:

CaF2 + H2SO4 -> CaSO4 + 2HF

CaF2 = 11g

H2SO4 = Used in excess

HF = 2.2 g production = Actual Yield

So, Let's write down the molar masses:

Molar Mass of CaF2 = 78 g /mol

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From the reaction, we can see the 1 mole of CaF2 gives the 2 moles of HF

i.e

a) Theoretical Yield of HF:

1 mole CaF2 = 2 moles HF

78 g CaF2 = 2 x 20 g of HF

78 g CaF2 = 40 g of HF

1 g CaF2 = 40g/78g of HF

And in the question it is given that chemist used 11 g of CaF2 so,

1 x 11 g of CaF2 = 11 x 40/78 g of HF

11 g of CaF2 = 440/78 g of HF

11 g of CaF2 = 5.64 g of HF

And this is the theoretical yield

Theoretical Yield of HF = 5.64 grams

b) Now, calculate the Percentage Yield of HF

Percentage Yield = Actual Yield /Theoretical Yield x 100

Percentage Yield = 2.2 g /5.64 g x 100

Percentage Yield = 39%

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2 years ago

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Answer:

This is due to the water moisture present in the recovered sample.

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2 years ago