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Zina [86]
2 years ago
13

Which statement is incorrect regarding the reaction of benzene with an electrophile? View Available Hint(s) A) The carbocation i

ntermediate loses a proton from the carbon bonded to the electrophile. B) Carbocation formation is the rate-determining step. C) Benzene functions as a nucleophile. D) The carbocation intermediate reacts with a nucleophile to form the addition product.

Chemistry
1 answer:
Leno4ka [110]2 years ago
3 0

Answer:

The carbocation intermediate reacts with a nucleophile to form the addition product.

Explanation:

The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.

The general mechanism is shown in the figure.

i) Attack of the electrophile on the benzene (which is the nucleophile)

ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.

iii) the carbocation formation is the rate determining step.

iv) There is no formation of addition product.

Thus the wrong statement is

The carbocation intermediate reacts with a nucleophile to form the addition product.

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The following chemical reaction takes place in aqueous solution: AgF (aq)+ NH4Cl (aq) →AgCl(s)+ NH4F(aq) Write the net ionic equ
Nadusha1986 [10]

Answer:

  • <em>The net ionic equation is: </em><u>Ag⁺ (aq) + Cl ⁻ (aq) → AgCl (s)</u>

Explanation:

<u>1) Start by writing the total ionic equation:</u>

The total ionic equation shows each aqueous substance in its ionized form, while the solid or liquid substances are shown with their chemical formula.

These are the ionic species:

  • AgF (aq) → Ag⁺ (aq) + F⁻ (aq)

  • NH₄Cl (aq) → NH₄⁺ (aq) + Cl ⁻ (aq)

  • NH₄F(aq) → NH₄⁺ (aq) + F⁻ (aq)

Then, replace each chemical formula in the chemical equation by those ionic forms:

  • Ag⁺ (aq) + F⁻ (aq) +  NH₄⁺ (aq) + Cl ⁻ (aq) → AgCl (s) + NH₄⁺ (aq) + F⁻ (aq)

That is the total ionic equation.

<u>2) Spectator ions:</u>

The ions that appear in both the reactant side and the product side are considered spectator ions (they do not change), and so they are canceled.

In our total ionic equation they are F⁻ (aq) and  NH₄⁺ (aq).

After canceling them, you get the net ionic equation:

<u>3) Net ionic equation:</u>

  • Ag⁺ (aq) + Cl ⁻ (aq) → AgCl (s)     ← answer

4 0
2 years ago
Which coefficient correctly balance the equation CaO + H2O -&gt; Ca(OH)2
deff fn [24]

For the equation that we are given:

CaO+H_{2}O → Ca(OH)_{2}

We see that on the reactants side we have:

Ca: 1 mol

O: 2 mol

H: 2 mol

And then we see that on the products side we have:

Ca: 1 mol

O: 2 mol

H: 2 mol

Therefore since we have equal moles of each of the elements on both sides of the equation, this equation is balanced how it is.

So the correct coefficients for this equation are: B) 1, 1, 1.

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You heat 51 grams of magnesium over a Bunsen burner for several minutes until it reacts with oxygen in the air. Then you weigh t
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Answer:

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8 0
2 years ago
In a conductivity apparatus, like the one above, you should never touch the ___ while the power is on. A Light Bulb B Leads C Wi
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Explanation:

5 0
2 years ago
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What is the molarity of 225 mL of a KNO3 solution containing 34.8 g KNO3? (molar mass = 101.1 g/mol)
Charra [1.4K]

Answer:

The answer to your question is the letter B) 1.53 M

Explanation:

Data

Molarity = ?

volume = 225 ml

mass of KNO₃ = 34.8 g

molar mass = 101.1 g/mol

Process

1.- Convert the ml to liters

                  1000 ml ------------------ 1 l

                   225 ml ------------------- x

                   x = (225 x 1) / 1000

                   x = 0.225 l

2.- Convert the mass of KNO₃ to moles

                  101.1 g ---------------------- 1 mol

                   34.8 g --------------------- x

                        x = (34.8 x 1) / 101.1

                        x = 0.344 moles

3.- Calculate the Molarity

Molarity = moles/volume

-Substitution

Molarity = 0.344/ 0.225

-Result

Molarity = 1.53 M

6 0
2 years ago
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