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steposvetlana [31]
2 years ago
5

a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre

d to a container with a volume of 18.5L
Chemistry
1 answer:
zhannawk [14.2K]2 years ago
3 0
To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

P1V1 = P2V2,

Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

(215 torr)(51 mL) =(“x” torr)(18,500 mL)
x = 0.593 torr

The final pressure exerted by the gas would be 0.593 torr.

Hope this helps!
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The halogens, alkali metals, and alkaline earth metals have __________ valence electrons, respectively.
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The valence electrons are as follows for these groups of elements:

Halogen- SEVEN  (halogens are group 7 elements that need one electron for the octet rule to be achieved)

Alkali Metals - ONE  (these are group one elements that lose a single electron to form an octet and cation)

Alkaline Earth Metals - TWO (group two elements that lose two electrons to form 2+ cations)

8 0
2 years ago
According to the equation below, how many moles of Ca(OH)2 are required to react with 1.36 mol H3PO4 to produce Ca3(PO4)2? 3Ca(O
allsm [11]

<u>Answer:</u> The amount of calcium hydroxide needed to react is 2.04 moles

<u>Explanation:</u>

We are given:

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By Stoichiometry of the reaction:

2 moles of phosphoric acid reacts with 3 moles of calcium hydroxide

So, 1.36 moles of phosphoric acid will react with = \frac{3}{2}\times 1.36=2.04mol of calcium hydroxide

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the correct answer is

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A student heats a sample of Copper (II) sulfate in a crucible and records the data shown in the table. What is the complete form
liberstina [14]

Explanation:

Copper (II) sulfate is usually present as a hydrous state, which is of the form CuSO4 * nH2O, where n is a whole number.

Mass of sample (CuSO4 * nH2O)

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Mass of water loss during heating

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= 23.90g - 4.40g = 19.50g

Molar mass of CuSO4 = 159.61g/mol

Moles of CuSO4 in sample

= 19.50g / (159.61g/mol) = 0.122mol.

Since mole ratio of CuSO4 to H2O

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Hence we have CuSO4 * 2H2O.

6 0
2 years ago
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