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Finger [1]
2 years ago
11

What is the molarity of 225 mL of a KNO3 solution containing 34.8 g KNO3? (molar mass = 101.1 g/mol)

Chemistry
2 answers:
Charra [1.4K]2 years ago
6 0

Answer:

The answer to your question is the letter B) 1.53 M

Explanation:

Data

Molarity = ?

volume = 225 ml

mass of KNO₃ = 34.8 g

molar mass = 101.1 g/mol

Process

1.- Convert the ml to liters

                  1000 ml ------------------ 1 l

                   225 ml ------------------- x

                   x = (225 x 1) / 1000

                   x = 0.225 l

2.- Convert the mass of KNO₃ to moles

                  101.1 g ---------------------- 1 mol

                   34.8 g --------------------- x

                        x = (34.8 x 1) / 101.1

                        x = 0.344 moles

3.- Calculate the Molarity

Molarity = moles/volume

-Substitution

Molarity = 0.344/ 0.225

-Result

Molarity = 1.53 M

Hunter-Best [27]2 years ago
6 0

Answer:

B, 1.53 M

Explanation:

Molarity = Moles/ Liter

Moles= 34.8g (1 mol/ 101 g) = .34 mol

Molarity= .34 mol/ .225 L = 1.53M KNO3

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Which is the stronger acid in each of the following pairs? Explain your reasoning.
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Explanation:

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The pKa value of o-fluorophenol is 8.7, while that of the p-fluorophenol is 9.9. It's obvious that the inductive effect is more dominant at ortho-position, which results in a more acidic nature

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6 0
2 years ago
there is a total of seventeen constitutional isomers for the molecular formula c5h13n. draw the skeletal formula of all three co
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5 0
2 years ago
Which of the following is not the same as 0.032 liters?
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This question needs the answer choices.

I found these choices for you:
<span>0.00032hL
320cL
32mL

Then  you need to make the conversion of 0.032 liters to hectoliters, centiliters and milimilters to check which is not equivalent.

1) 0.032 liters to hectoliters:

    0.032 liter *  1 hectoliter / 100 liter = 0.00032 hecoliter

2) 0.032 liter to centiliters:

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3 0
2 years ago
Small quantites of hydrogen gas can be prepared in the laboratory by the addition of aqueous hydrochloric acid to metallic zinc.
ira [324]

<u>Answer:</u> The mass or zinc reacted is 0.624 grams.

<u>Explanation:</u>

We are given:

Total pressure = 1.032 atm

Vapor pressure of water = 32 torr = 0.042 atm    (Conversion factor:  1 atm = 760 torr)

To calculate partial pressure of hydrogen gas, we use the equation:

p_{H_2}=p_T-p_{H_2O}\\\\p_{H_2}=1.032-0.042=0.99atm

To calculate the number of moles of hydrogen gas, we use the equation given by ideal gas follows:

PV=nRT

where,

P = pressure of hydrogen gas = 0.99 atm

V = Volume of hydrogen gas = 240. mL = 0.240 L    (Conversion factor: 1 L = 1000 mL)

T = Temperature of hydrogen gas = 30^oC=[30+273]K=303K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of hydrogen gas = ?

Putting values in above equation, we get:

0.99atm\times 0.240L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 303K\\n=\frac{0.99\times 0.240}{0.0821\times 303}=9.55\times 10^{-3}mol

The chemical equation for the reaction of zinc and hydrochloric acid follows:

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By Stoichiometry of the reaction:

1 mole of hydrogen gas is produced from 1 mole of zinc metal

So, 9.55\times 10^{-3}mol of hydrogen gas is produced from = \frac{1}{1}\times 9.55\times 10^{-3}=9.55\times 10^{-3}mol of zinc metal

To calculate the mass of zinc metal, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of zinc = 65.38 g/mol

Moles of zinc = 9.55\times 10^{-3} moles

Putting values in above equation, we get:

9.55\times 10^{-3}mol=\frac{\text{Mass of zinc}}{65.38g/mol}\\\\\text{Mass of zinc}=(9.55\times 10^{-3}mol\times 65.38g/mol)=0.624g

Hence, the mass or zinc reacted is 0.624 grams.

4 0
2 years ago
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