<span>x=((12.3/100)m)cos[(1.26s^−1)t]
v= dx/dt = -</span><span>((12.3/100)*1.26)sin[(1.26s^−1)t]
v=</span>-((12.3/100)*1.26)sin[(1.26s^−1)t]=-((12.3/100)*1.26)sin[(1.26s^−1)*(0.815)]
v=<span>
<span>-0.13261622 m/s
</span></span>the object moving at 0.13 m/s <span>at time t=0.815 s</span>
Answer:
1340.2MW
Explanation:
Hi!
To solve this problem follow the steps below!
1 finds the maximum maximum power, using the hydraulic power equation which is the product of the flow rate by height by the specific weight of fluid
W=αhQ
α=specific weight for water =9.81KN/m^3
h=height=220m
Q=flow=690m^3/s
W=(690)(220)(9.81)=1489158Kw=1489.16MW
2. Taking into account that the generator has a 90% efficiency, Find the real power by multiplying the ideal power by the efficiency of the electric generator
Wr=(0.9)(1489.16MW)=1340.2MW
the maximum possible electric power output is 1340.2MW
Answer:

Explanation:
The word 'nun' for thickness, I will interpret in international units, that is, mm.
We will begin by defining the intensity factor for the steel through the relationship between the safety factor and the fracture resistance of the panel.
The equation is,

We know that
is 33Mpa*m^{0.5} and our Safety factor is 2,

Now we will need to find the average width of both the crack and the panel, these values are found by multiplying the measured values given by 1/2
<em>For the crack;</em>

<em>For the panel</em>

To find now the goemetry factor we need to use this equation

That allow us to determine the allowable nominal stress,


\sigma_{allow} = 208.15Mpa
So to get the force we need only to apply the equation of Force, where



That is the maximum tensile load before a catastrophic failure.
It takes more energy to remove the second electron from a lithium atom than it does to remove the fourth electron from a carbon atom because its inner core e, not valence e. C's 4th removed e is still a valence e. And also <span>because more nuclear charge acting on the second electron, it is more close to the nucleus, thus the the protons attract it more than the 4th electron.</span>
To solve this problem it is necessary to take into account the concepts related to Centripetal Force and Friction Force.
In the case of the centripetal force, we know that it is defined as

Where,
m=mass
v= velocity
r= Radius
In the case of the Force of Friction we have to,

Where,
Friction Constant
m= mass
g= gravity
According to the information given, the centripetal force must be less than or equal to the friction force to stay on the road, in this way

Re-arrange to find the velocity,



Therefore la velocidad del carro debe ser igual o menor a 42m/s para mantenerse en el camino