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Svet_ta [14]
2 years ago
7

Antireflection coatings can be used on the inner surfaces of eyeglasses to reduce the reflection of stray light into the eye, th

us reducing eyestrain.PART A) A 90-nm-thick coating is applied to the lens. What must be the coating's index of refraction to be most effective at 480 nm? Assume that the coating’s index of refraction is less than that of the lens. n = _____ .PART B) If the index of refraction of the coating is 1.38, what thickness should the coating be so as to be most effective at 480 ? The thinnest possible coating is best.t = _____ nm .
Physics
1 answer:
TEA [102]2 years ago
6 0

Answer:

a) n = 1.33, b)  t = 87 10⁻⁹ m

Explanation:

Part A.

The thin anti-reflection film should create destructive interference for the desired wavelength.

      2t sin θ = (m + ½) λₙ

The 2 goes out of the path of the beam inside the film, lam is the wavelength modulated by the refractive index of the film

      λₙ =  λ₀ / n

      2t = (m + ½) λ₀ / n

      n = (m+ ½) λ₀/2t

Suppose we are in the first inference m = 0

     n = (½ 480 10-9)/ 2 90

     n = 1.33

Part B

We do not know the refractive index of the glass explicitly, but in general it is of the order of 1.5, so since the index of the film is lower, there is no phase change.

      2t = (m + ½) λ₀ / n

      t = 1/4 480 10⁻⁹ / 1.38

      t = 87 10⁻⁹ m

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What type of light does this light bulb produce most (i.e. at what wavelength does the spectrum have maximum intensity)?
lesantik [10]

Answer: The light bulb produces the continuous light. At minimum wavelength the spectrum have maximum intensity.

Explanation:

According to Wein's displacement law, the wavelength is inversely proportional to the temperature.

The intensity depends on the frequency. The frequency is inversely proportional to the wavelength.

Therefore, when the temperature of the light bulb will be maximum then the wavelength will be minimum. At minimum wavelength the spectrum have maximum intensity.

4 0
2 years ago
You are using a rope to lift a 14.5 kg crate of fruit. Initially you are lifting the crate at 0.500 m/s. You then increase the t
lina2011 [118]

Answer:

W = 172.5 J

Explanation:

given,                                    

mass of the fruit crate = 14.5 kg

initial velocity to lift = 0.500 m/s

increase in the tension = 150 N

lift of crate = 1.15 m                  

work done by the tension = ?        

work done  = force x displacement

W = F s cos θ                                

θ = 0°                                    

W = F s x cos 0                                  

W = 150 x 1.15 x 1                

W = 172.5 J                                      

Work done on the crate by the tension force = W = 172.5 J

5 0
2 years ago
Which of the following four circuit diagrams best represents the experiment described in this problem?
Valentin [98]

We don't see any circuit diagrams.  

This worries us for a few seconds, until we realize that we don't know anything about the experiment described in the problem either, so we don't have to worry about it at all.

6 0
2 years ago
A tennis ball bounces on the floor three times. If each time it loses 22.0% of its energy due to heating, how high does it rise
lesya692 [45]

Answer:

H = 109.14 cm

Explanation:

given,                                                            

Assume ,                                                            

Total energy be equal to 1 unit                                

Balance of energy after first collision = 0.78 x 1 unit

                                                             = 0.78 unit

Balance after second collision = 0.78 ^2 unit

                                                   = 0.6084 unit

Balance after third collision = 0.78 ^3 unit

                                              = 0.475 unit

height achieved by the third collision will be equal to energy remained                                        

H be the height achieved after 3 collision

0.475 ( m g h) = m g H                  

H = 0.475 x h                                    

H = 0.475 x 2.3 m                          

H = 1.0914 m                      

H = 109.14 cm                      

6 0
2 years ago
Two resistors of 5.0 and 9.0 ohm are connected in parallel. A 4.0 ohm resistor is then connected in series with the parallel com
rewona [7]

Answer:

I1 = 0.772 A

Explanation:

<u>Given</u>: R1 = 5.0 ohm, R2 = 9.0 ohm, R3 = 4.0 ohm, V = 6.0 Volts

<u>To find</u>:  current I = ? A

<u>Solution: </u>

Ohm's law  V= I R

⇒   I = V / R

In order to find R (total) we first find R (p) fro parallel combination. so

1 / R (p) = 1 / R1  + 1/ R2          ∴(P) stand for parallel

R (p) = R1R2 / ( R1 + R2)

R (p) = (5.0 × 9.0) / (5.0 + 9.0)

R (p) = 3.214 ohm

Now R (total) = R (p) + R3     (as R3 is connected in series)

R (total) = 3.214 ohm + 4.0 Ohm

R (total) = 7.214 ohm

now I (total) = 7.214 ohm / 6.0 Volts

I (total) = 1.202 A

This the total current supplied by 6 volts battery.

as voltage drop across R (p) = V = R (p) × I (total)

V (p) = 3.214 ohm × 1.202 A  = 3.864 volts

Now current through 5 ohms resister  is I1 = V (P) / R1

I1 = 3.864 volts / 5 ohm

I1 = 0.772 A

3 0
2 years ago
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