Write Lewis structures for the following molecules: (a) ICl, (b) PH3, (c) P4 (each P is bonded to three other P atoms), (d) H2S,
(e) N2H4, (f ) HClO3, (g) COBr2 (C is bonded to O and Br atoms).
1 answer:
Answer : The Lewis-dot structure for the following molecules are shown below.
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
Now we have to determine the Lewis-dot structure for the following molecules.
(a) The given molecule is,
As we know that iodine and chlorine have '7' valence electrons.
Therefore, the total number of valence electrons in = 7 + 7 = 14
According to Lewis-dot structure, there are 2 number of bonding electrons and 12 number of non-bonding electrons.
(b) The given molecule is,
As we know that phosphorous has '5' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in = 5 + 3(1) = 8
According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.
(c) The given molecule is,
As we know that phosphorous has '5' valence electrons.
Therefore, the total number of valence electrons in = 4(5) = 20
According to Lewis-dot structure, there are 6 number of bonding electrons and 14 number of non-bonding electrons.
(d) The given molecule is,
As we know that sulfur has '6' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in = 6 + 2(1) = 8
According to Lewis-dot structure, there are 4 number of bonding electrons and 4 number of non-bonding electrons.
(e) The given molecule is,
As we know that nitrogen has '5' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in = 2(5) + 4(1) = 14
According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.
(f) The given molecule is,
As we know that chlorine has '7' valence electrons, oxygen has '6' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in = 1 + 7 + 3(6) = 26
According to Lewis-dot structure, there are 12 number of bonding electrons and 14 number of non-bonding electrons.
(g) The given molecule is,
As we know that bromine has '7' valence electrons, oxygen has '6' valence electrons and carbon has '4' valence electrons.
Therefore, the total number of valence electrons in = 4 + 6 + 2(7) = 24
According to Lewis-dot structure, there are 8 number of bonding electrons and 16 number of non-bonding electrons.
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Answer:
B = CHCl2 + Cl2 --> CHCl3 + Cl
Explanation:
Free radical halogenation is a chlorination reaction on Alkane hydrocarbons. This involves the splitting of molecules into radicals/ unstable molecules in the presence of sunlight/ U.V light which ensures bonding of the molecules.
Free radical chlorination is divided into 3 steps which are:
The initiation step
The propagation step
The termination step
So in reference to the question, propagation step involves two steps.
The first step is where the molecule in this case the methylene chloride(CH2Cl2) loses a hydrogen atom and then bond with a chlorine atom radical to give a nethylwnw chloride radical and HCl.
The second step involves the reaction of this methylene chloride got in the first step with chlorine molecule to form trichloride methane and a chlorine radical.
You would find in the attachment the 2 step mechanism.
