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Kamila [148]
2 years ago
15

A line contains the points (8,9) and (-12, -7). Using point-slope form, write the equation of the line that is parallel to the g

iven
line and that passes through (-5, -15).
A) y-15= -5/4 (x-5)
B) y+15= -5/4 (x+5)
C) y+5= 4/5 (x+15)
D) y+15= 4/5 (x+5)
Mathematics
1 answer:
pogonyaev2 years ago
4 0

Answer:

D. y+15 = 4/5(x+5)

Step-by-step explanation:

A line contains the points (8,9) and (-12, -7).

(y2 - y1) = m(x2 - x1)

(9 - (-7))= m (8 -(-12))

16 = m*20

m = 16/20 = 4/5

Given line has slope m= 4/5.

Parallel line has the same slope m = 4/5.

Point-slope equation is (y - y1) = m(x - x1).

We have slope m = 4/5, and point (-5, -15).

So,

(y - (-15)) = 4/5(x - (-5))

y+15 = 4/5(x+5)

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While measuring specimens of nylon yarn taken from two spinning machines, it was found that 9 specimens from the first machine h
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kaaaaaaaaaaaaaaaaabbbichaStep-by-step explanation:

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2 years ago
At a rally attended by 520 people, 30% were fantes, 25% were ewes, 15% were nzemas, 20% were gas and the rest were gonjas. How m
mariarad [96]

Answer:

No. of gonjas = 52

No. of more nzemas than fantes = 78

Step-by-step explanation:

Total no. of people = 520

No. of fantes = \frac{30}{100} × 520

No. of fantes = 156

No. of ewes = \frac{25}{100} × 520 = 130

No. of nzemas = \frac{15}{100} × 520 = 78

No. of gas = \frac{20}{100} × 520 = 104

No. of gonjas = 520 - (156 + 130 + 78 + 104) = 52

No. of fantes = 156

No. of nzemas = 78

No. of more nzemas than fantes = 156 - 78 = 78

Pie chart of the following problem is shown below.

5 0
2 years ago
Read 2 more answers
If line A contains Q(5,1) and is parallel to line MN with M(-2,4) and N(2,1), which ordered pair would be on the perpendicular t
vivado [14]
Your question does not say what were your options, therefore I will answer generically: in order to understand if a point (ordered pair) is contained in a line, you need to substitute the x-component of the pair in the equation of the line and see if the calculations give you the y-component of the pair.

Example:
Your line is <span> y = 4/3x + 1/3
Let's see if <span>(0, 0) and (2, 3) </span>belong to this line

y</span> = <span>4/3·0 + 1/3 = 1/3 </span>≠ 0
Therefore, the line does not contain (0, 0)

y = 4/3·2 + 1/3 = 9/3 = 3
Therefore, the line contains (2, 3)

6 0
2 years ago
Read 2 more answers
A linear regression equation is calculated for a sample of n = 20 pairs of X and Y values.
Nata [24]

Answer: B) 18

Step-by-step explanation:

The degree of freedom for Standard error or df(Residual) is the sample size minus the number of estimated parameters ,.

df= n - p  , where n= sample size , p = number of parameters.

According to the given problem , we have

Sample size : n=20

Number of parameters (x and y ): p= 2

Then, the df value for the standard error of estimate will be :

df= n-p =20-2=18

Thus , the df value for the standard error of estimate is 18 .

Hence, the correct answer is B) 18 .

3 0
2 years ago
An entrepreneur estimates his total profit (total revenue minus total cost) for his proposed company as p(x) = x3 − 4x2 + 5x − 2
RideAnS [48]

Answer:

Year in which the entrepreneur break even is 4

Step-by-step explanation:

We are given:

p(x) = x^3-4x^2+5x-20

We would find the value of x

Solving:

x^3-4x^2+5x-20 = 0

(x^3-4x^2)+(5x-20) = 0

x^2(x-4)+5(x-4) = 0

(x-4)(x^2+5)=0

=> x-4 = 0 and x^2+5 =0

x = 4 and x^2 = -5

x = 4 and x = ±√-5 or ±√5 i (not real solutions)

So, x = 4

So, year in which the entrepreneur break even is 4

4 0
2 years ago
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