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Brut [27]
2 years ago
8

A mover pushes a 30.0 kg crate across a wooden floor at a constant speed of 0.75 m/s. If the coefficient of static friction for

wood-on-wood is 0.20, what is the normal force exerted by the floor on the crate?
Physics
1 answer:
liraira [26]2 years ago
3 0

Answer:

294.3 N

Explanation:

In this situation, we are told that the crate is not accelerating in the horizontal plane. But also it is not accelerating in the vertical plane. Meaning that the sum of all vertical forces add up to zero.

Fnet =  ma

Weight + Normal force = mass *  acceleration

-(30 kg * 9.81 m/s²) + Normal force = 30.0 kg * 0 m/s²

                                  Normal force = 294.3 N

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Given:
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A flashlight beam makes an angle of 60 degrees with the surface of the water before it enters the water. in the water what angle
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<h3><u>Answer</u>;</h3>

= 22°

<h3><u>Explanation</u>;</h3>
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Two identical boxes are being pulled across a horizontal floor at a constant velocity by a horizontal pulling force of 176 N tha
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Answer:

the tension in the rope between the boxes is equal to 88 N

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so, the tension in the rope between the boxes is equal to 88 N

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