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2 years ago

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A direct variation function contains the points (–9, –3) and (–12, –4). Which equation represents the function? y = –3x y = –y e

quals StartFraction x Over 3 EndFraction. y = y equals StartFraction x Over 3 EndFraction. y = 3x

2 answers:

atroni [7]2 years ago

6 0

Answer:

The equation which represents the function is given by,

x = 3y .

Step-by-step explanation:

The direct variation function contains the points, (-9, -3) and (-12, -4).

Here,

$\frac {-9}{-3} = \frac {-12}{-4}$ = 3

So, the equation which represents the function is given by,

x = 3y .

Marysya12 [62]2 years ago

6 0

Answer:

x = 3y

Step-by-step explanation:

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At a particular restaurant, each onion ring has 45 calories and each chicken wing has 65 calories. A combination meal with onion

IceJOKER [234]

Answer:

$Number\ of\ chicken\ rings=5\\\\Number\ of\ onion\ rings=10$

Step-by-step explanation:

$Let\ number\ of\ chicken\ rings=x\\\\Number\ of\ onion\ rings=Number\ of\ chicken\ rings+5=x+5\\\\$

Calories:

$Calories\ in\ 1\ chicken\ ring=45\\\\Total\ calories\ because\ of\ onion\ ring=45\times Number\ of\ onion\ ring\\\\Total\ calories\ because\ of\ onion\ ring=45\times(x+5)=45x+225\\\\Calories\ in\ 1\ onion\ ring=65\\\\Total\ calories\ because\ of\ chicken\ ring=65\times Number\ of\ chicken\ ring\\\\Total\ calories\ because\ of\ chicken\ ring=65x\\\\Total\ calories=Calories\ because\ of\ onion\ ring+Calories\ because\ of\ chicken\ ring\\\\Total\ calories=45x+225+65x\\\\Tota\ calories=110x+225$

$Given\ total\ calories=775\\\\110x+225=775\\\\110x=775-225\\\\110x=550\\\\x=5\\\\Number\ of\ chicken\ rings=5\\\\Number\ of\ onion\ rings=5+5=10$

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2 years ago

Compute the least-squares regression line for predicting y from a given the following summary statistics. Round final answers to

qwelly [4]

Answer: Regression line equation: $\hat{y}=-1.008x+39.1704$

Step-by-step explanation:

Equation of least-squares regression line for predicting y :

$\hat{y}=b_1x+b_o$

, where $\text{Slope} (b_1)=r\dfrac{s_y}{s_x}$ , $\text{intercept}(b_0)=\bar{y}-b_1\bar{x}$

Given: $\bar{x}=8.8,\ s_x=1.5,\ s_y=1.8,\ \bar{y}=30.3,\ r=-0.84$

Then,

$b_1=(-0.84)\dfrac{ 1.8}{ 1.5}\\\\\Rightarrow\ b_1=-1.008$

Now,

$b_0=30.3-(-1.008)(8.8)=30.3+8.8704\\\\\Rightarrow\ b_0=39.1704$

Then, Regression line equation: $\hat{y}=-1.008x+39.1704$

6 0

2 years ago

4(g - 1 )=24<br>what is the answer

babunello [35]

Hello There!

First Expand:
4g - 4 = 24
Then solve:
4g = 24 + 4
4g = 28
g = 28/4
g = 7.

Hope This Helps You!
Good Luck :)

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2 years ago

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Explain how making a table helps to compare two or more sets of data that have been presented in different ways.

vlabodo [156]

Making a table helps compare two or more sets of data because you can see how much it has increased or decreased.

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2 years ago

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Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

2 years ago