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Brut [27]
2 years ago
7

When a pendulum is pulled back from its equilibrium position by 10∘, the restoring force is 1.0 N. When it is pulled back to 30∘

, the force increases to 2.8 N. If the pendulum is then released from 30∘, will its motion be periodic? If the pendulum is then released from 30, will its motion be periodic?a) No, it will be linear motion.b) No, the motion will be chaotic.c)Yes and it will be exactly harmonic.d)Yes, but it will not be exactly harmonic.
Physics
2 answers:
jarptica [38.1K]2 years ago
5 0

Answer: B

Explanation: I said B because if you pull something back what is going to be more of a force pulling back or letting it go for a rubier band yes it will have more force if you let it go

fenix001 [56]2 years ago
3 0

Answer:

The answer is d) Yes, but it will not be exactly harmonic: the pendulum’s motion will be periodic, but will not be exactly harmonic because the condition for simple harmonic motion is not satisfied when angular displacements become larger. Typically, a pendulum’s motion will exhibit simple harmonic motion if angular displacements are smaller.

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vagabundo [1.1K]

Answer:

The maximum amount of mechanical energy converted to internal energy during the fall is 26.7 joules

Explanation:

Potential Energy (PE) = weight of baseball × height = 1.47N × 10m = 14.7Nm = 14.7 joules

Kinetic Energy (KE) = 12 joules

Maximum amount of mechanical energy converted to internal energy during the fall = PE + KE = 14.7 joules + 12 joules = 26.7 joules

8 0
2 years ago
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The boom hoisting sheave must have pitch diameters of no less than _______times the nominal diameter of the rope used.
alexira [117]

Answer:

18 times

Explanation:

According to the security purposes which is set under the rules and regulation OSHA, which describes all the rights to the worker.

In the boom hoist receiving system all the sheaves which are used should have a pitch diameter of rope not less than 18 times the diameter of the nominal rope which is used.

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2 years ago
3-m-high large tank is initially filled with water. The tank water surface is open to the atmosphere, and a sharp-edged 10-cm-di
irinina [24]

Answer:

The initial velocity of the water from the tank is 5.42 m/s

Explanation:

By applying Bernoulli equation between  point 1 and 2

\dfrac{P_1}{\rho g}+\dfrac{V_1^2}{2g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{V_2^2}{2g}+Z_2+h_L

At the point 1

P₁=0  ( Gauge pressure)

V₁= 0 m/s

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At point 2

P₂=0  ( Gauge pressure)

Z₂= 0 m/s

h_L=1.5\ m

Now by putting the values

\dfrac{P_1}{\rho g}+\dfrac{V_1^2}{2g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{V_2^2}{2g}+Z_2+h_L

Z_1-h_L=\dfrac{V_2^2}{2g}

3-1.5=\dfrac{V_2^2}{2\times 9.81}

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The initial velocity of the water from the tank is 5.42 m/s

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3 years ago
The air in a pipe resonates at 150 Hz and 750 Hz, one of these resonances being the fundamental. If the pipe is open at both end
Xelga [282]

Answer:

Explanation:

Two frequencies with magnitude 150 Hz and 750 Hz are given

For Pipe open at both sides

fundamental frequency is 150 Hz as it is smaller

frequency  of pipe is given by

f=\frac{nv}{2L}

where L=length of Pipe

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f=150\ Hz for n=1

and f=750 is for n=5

thus there are three resonance frequencies for n=2,3 and 4

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for n=0

f_1=\frac{v}{4L}

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for n=2

f_2=\frac{5v}{4L}

Thus there is one additional resonance corresponding to n=1 , between f_1 and f_2

8 0
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