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strojnjashka [21]
2 years ago
10

If the peak wavelength of a star at rest is 1375 nm, then what peak wavelength is observed when the star is traveling 975,000 m/

s away from the Earth.
Physics
1 answer:
Feliz [49]2 years ago
6 0

The concept required to solve this problem is that of the Doppler effect which is defined as the change in frequency of a wave in relation to an observer who is moving relative to the wave source

Mathematically it can be expressed as

\frac{\lambda_0-\lambda_s}{\lambda_s} = \frac{v}{c}

Where,

c = Speed of light

\lambda_0 = Peak wavelength

\lambda_s = Peak Wavelength observed

Our values are given as,

v=975000m/s

c = 3*10^8m/s \rightarrow Speed of light

\lambda_s = 1375*10^{-9}m

Basically what we should look for is that 'relative' frequency that is emitted when the star moves away so we clear \lambda_s

Replacing we have,

\frac{\lambda_0-\lambda_s}{\lambda_s} = \frac{v}{c}

\frac{\lambda_0-1375*10^{-9}}{1375*10^{-9}} = \frac{975000}{3*10^8}

\lambda_0 = 1379.46nm

Therefore the peak wavelength that is observed when the star is traveling away from the eart to the velocity given is 1379.46nm

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Answer

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by rearranging the equation we can say

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Answer:

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By applying the derivative you obtain:

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