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irga5000 [103]
2 years ago
14

An electric toaster is rated 1200 watts at 120 volts. what is the total electrical energy used to operate the toaster for 30 sec

onds?
Physics
1 answer:
Anarel [89]2 years ago
3 0
Energy is calculated as power*time, so give the wattage of 1200 W (equivalent to 1200 Joules/second) and time of 30 seconds, multiplying these gives 36000 J or 36 kJ of electrical energy.

If electrical charge or current is needed: Power = voltage * current, so given the power of 1200 watts and voltage of 120 V, current is 1200 W / 120 V = 10 Amperes. Charge is calculated by multiplying 10 A*30 s = 300 C.
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What voltage is required to move 6A through 20?<br><br>​
Marina CMI [18]

Answer:

120V

Explanation:

Given parameters:

Current  = 6A

Resistance  = 20Ω

Unknown:

Voltage = ?

Solution:

According to ohms law;

           V = IR

Where V is the voltage

            I is the current

            R is the resistance

Now, insert the parameters and solve;

    V  = 6 x 20  = 120V

7 0
2 years ago
Our two intrepid relacar drivers are named Pam and Ned. We use these names to make it easy to remember: measurements made by Pam
zhannawk [14.2K]

The velocity of Ned as measured by Pam is the interpretation of v.

Answer: Option D

<u>Explanation:</u>

According to question, we know that this is an issue depending on the logical and translation of the factors. From the measured information taken what is gathered by the two people is communicated and we have given as:

The Ned reference framework : (x, t)  

The Pam reference framework :  \left(x^{\prime}, t^{\prime}\right)

From the reference framework, we realize that ν is the speed of Pam (the other reference framework) as estimation by Ned.  

At that point, v^{\prime} is the speed of Ned (from the other arrangement of the reference) as estimation by Pam.

3 0
2 years ago
A free-falling golf ball strikes the ground and exerts a force on it. Which sentences are true about this situation? A golf ball
Harlamova29_29 [7]

Answer:

The ground exerts an equal force on the golf ball

Explanation:

Third's Newton Law states that:

"When an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A".

In this problem, object A is the golf ball while object B is the ground, so we can say that:

- the golf ball exerts a force on the ground

- the ground exerts an equal and opposite force on the golf ball

8 0
2 years ago
Read 2 more answers
A compact, dense object with a mass of 2.90 kg is attached to a spring and is able to oscillate horizontally with negligible fri
enot [183]

(a) 80 N/m

The spring constant can be found by using Hooke's law:

F=kx

where

F is the force on the spring

k is the spring constant

x is the displacement of the spring relative to the equilibrium position

At the beginning, we have

F = 16.0 N is the force applied

x = 0.200 m is the displacement from the equilibrium position

Solving the formula for k, we find

k=\frac{F}{m}=\frac{16.0 N}{0.200 m}=80 N/m

(b) 0.84 Hz

The frequency of oscillation of the system is given by

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

where

k = 80 N/m is the spring constant

m = 2.90 kg is the mass attached to the spring

Substituting the numbers into the formula, we find

f=\frac{1}{2\pi}\sqrt{\frac{80 N/m}{2.90 kg}}=0.84 Hz

(c) 1.05 m/s

The maximum speed of a spring-mass system is given by

v=\omega A

where

\omega is the angular frequency

A is the amplitude of the motion

For this system, we have

\omega=2\pi f=2\pi (0.84 Hz)=5.25 rad/s

A=0.200 m (the amplitude corresponds to the maximum displacement, so it is equal to the initial displacement)

Substituting into the formula, we find the maximum speed:

v=(5.25 rad/s)(0.200 m)=1.05 m/s

(d) x = 0

The maximum speed in a simple harmonic motion occurs at the equilibrium position. In fact, the total mechanical energy of the system is equal to the sum of the elastic potential energy (U) and the kinetic energy (K):

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2

where

k is the spring constant

x is the displacement

m is the mass

v is the speed

The mechanical energy E is constant: this means that when U increases, K decreases, and viceversa. Therefore, the maximum kinetic energy (and so the maximum speed) will occur when the elastic potential energy is minimum (zero), and this occurs when x=0.

(e) 5.51 m/s^2

In a simple harmonic motion, the maximum acceleration is given by

a=\omega^2 A

Using the numbers we calculated in part c):

\omega=2\pi f=2\pi (0.84 Hz)=5.25 rad/s

A=0.200 m

we find immediately the maximum acceleration:

a=(5.25 rad/s)^2(0.200 m)=5.51 m/s^2

(f) At the position of maximum displacement: x=\pm 0.200 m

According to Newton's second law, the acceleration is directly proportional to the force on the mass:

a=\frac{F}{m}

this means that the acceleration will be maximum when the force is maximum.

However, the force is given by Hooke's law:

F=kx

so, the force is maximum when the displacement x is maximum: so, the maximum acceleration occurs at the position of maximum displacement.

(g) 1.60 J

The total mechanical energy of the system can be found by calculating the kinetic energy of the system at the equilibrium position, where x=0 and so the elastic potential energy U is zero. So we have

E=K=\frac{1}{2}mv_{max}^2

where

m = 2.90 kg is the mass

v_{max}=1.05 m/s is the maximum speed

Solving for E, we find

E=\frac{1}{2}(2.90 kg)(1.05 m/s)^2=1.60 J

(h) 0.99 m/s

When the position is equal to 1/3 of the maximum displacement, we have

x=\frac{1}{3}(0.200 m)=0.0667 m

so the elastic potential energy is

U=\frac{1}{2}kx^2=\frac{1}{2}(80 N/m)(0.0667 m)^2=0.18 J

and since the total energy E = 1.60 J is conserved, the kinetic energy is

K=E-U=1.60 J-0.18 J=1.42 J

And from the relationship between kinetic energy and speed, we can find the speed of the system:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(1.42 J)}{2.90 kg}}=0.99 m/s

(i) 1.84 m/s^2

When the position is equal to 1/3 of the maximum displacement, we have

x=\frac{1}{3}(0.200 m)=0.0667 m

So the restoring force exerted by the spring on the mass is

F=kx=(80 N/m)(0.0667 m)=5.34 N

And so, we can calculate the acceleration by using Newton's second law:

a=\frac{F}{m}=\frac{5.34 N}{2.90 kg}=1.84 m/s^2

8 0
2 years ago
A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.
MakcuM [25]

Answer:

b. 9.5°C

Explanation:

m_i = Mass of ice = 50 g

T_i = Initial temperature of water and Aluminum = 30°C

L_f = Latent heat of fusion = 3.33\times 10^5\ J/kg^{\circ}C

m_w = Mass of water = 200 g

c_w = Specific heat of water = 4186 J/kg⋅°C

m_{Al} = Mass of Aluminum = 80 g

c_{Al} = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C

The final equilibrium temperature is 9.50022°C

4 0
2 years ago
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