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Katyanochek1 [597]
2 years ago
13

addition of sulfurous acid (a weak acid) to barium hydroxide ( a strong base) results in the formation of a precipitate. The net

ionic equation for this reaction is
Chemistry
1 answer:
Trava [24]2 years ago
7 0

net ionic equation:

SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)

Explanation:

We have the following chemical reaction:

H₂SO₄ (aq) + Ba(OH)₂ (aq) → BaSO₄ (s) + 2 H₂O (l)

Now we write the ionic equation:

2 H⁺ (aq) + SO₄²⁻ (aq) + Ba²⁺ (aq) + 2 OH⁻ (aq) → BaSO₄ (s) + 2 H⁺ + 2 OH⁻ (aq)

We remove the spectator ions to obtain the net ionic equation:

SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)

where we have:

(aq) - aqueous

(s) - solid

(l) - liquid

Learn more about:

net ionic equation

brainly.com/question/7018960

#learnwithBrainly

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Draw a structure containing only carbon and hydrogen that is a stable alkyne of five carbons containing a ring.
stepladder [879]

Answer:

                     Ethynylcyclopropane is the stable isomer for given alkyne.

Explanation:

                     In order to solve this problem we will first calculate the number of Hydrogen atoms. The general formula for alkynes is as,

                                                    CₙH₂ₙ₋₂

Putting value on n = 5,

                                                    C₅H₂.₅₋₂

                                                    C₅H₈

Also, the statement states that the compound contains one ring therefore, we will subtract 2 hydrogen atoms from the above formula i.e.

                      C₅H₈   ------------(-2 H) ---------->  C₅H₆

Hence, the molecular formula for given compound is C₅H₆

Below, 4 different isomers with molecular formula C₅H₆ are attached.

                                      The first compound i.e. ethynylcyclopropane is stable. As we know that alkynes are sp hybridized. The angle between C-C-H in alkynes is 180°. Hence, in this structure it can be seen that the alkyne part is linear and also the cyclopropane part is a well known moiety.

                                      Compounds 3-ethylcycloprop-1-yne, <u>cyclopentyne </u>and 3-methylcyclobut-1-yne are highly unstable. The main reason for the instability is the presence of triple bond in three, five and four membered ring. As the alkynes are linear but the C-C-H bond in these compound is less than 180° which will make them highly unstable.

5 0
2 years ago
A student is given a sample of CuSO4(s) that contains a solid impurity that is soluble and colorless. The student wants to deter
DochEvi [55]

Answer:

The impurity which is present in the solution of copper sulphate (CuSO4) is determined by the an instrument known as spectrophotometer.

Explanation:

Spectrophotometer is a device or an instrument which is used to determine the concentration of a chemical by measuring the detection of light intensity that is coming from the solution. If the solution of copper sulphate is checked through spectrophotometer, we can can determined or measure the amount of copper sulphate and the impurity in the solution.

3 0
2 years ago
A 0.25 m solution of the sugar sucrose (c12h22o11) in water is tested for conductivity using the type of apparatus shown. Bulb w
Anvisha [2.4K]

Sucrose is a non ionic compound. It does liberates ion when dissolved in water unlike NaCl or other salts which dissolve in water and produce respective cations and anions.

Thus if any amount of sucrose is dissolved in water, it will form non ionic aqueous solution (it will dissolve completely). Thus sucrose solution being non electrolytic will not conduct electricity in aqueous solution.

the bulb will not light up as sucrose will remain in molecular form only

6 0
2 years ago
1. Draw the basic repeating unit of sodium alginate polymer. 2. What is this polymer used for?
tamaranim1 [39]

Answer:

1.The diagram is attached

2.sodium alginate is a polymer which can be extracted from brown seaweed and is used for defloculating, gelling and thickening

Used also in dermatological preparation

Used in adhensive paste

8 0
2 years ago
Read 2 more answers
1. A student sees tiny bubbles clinging to the inside of an unopened plastic bottle full of carbonated soft drinks. The student
Lina20 [59]

Answer:

1) The bubbles will grow, and more may appear.

2)Can A will make a louder and stronger fizz than can B.

Explanation:

When you squeeze the sides of the bottle you increase the pressure pushing on the bubble, making it compress into a smaller space. This decrease in volume causes the bubble to increase in density. When the bubble increases in density, the bubble will grow and more bubbles will appear. Therefore, Changing the pressure (by squeezing the bottle) changes the volume of the bubbles. The number of bubbles doesn't change, just their size increases.

Carbonated drinks tend to lose their fizz at higher temperatures because the loss of carbon dioxide in liquids is increased as temperature is raised. This can be explained by the fact that when carbonated liquids are exposed to high temperatures, the solubility of gases in them is decreased. Hence the solubility of CO2 gas in can A at 32°C is less than the solubility of CO2 in can B at 8°C. Thus can A will tend to make a louder fizz more than can B.

3 0
2 years ago
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