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2 years ago

The radius of a hailstone varies directly with

Mathematics

1 answer:

maw [93]2 years ago

4 0

Answer:

Hailstone remained in the cloud for 25 seconds.

Step-by-step explanation:

Radius of a hailstone varies directly with the duration for which it was in the cloud.

Let the radius of the hailstone is 'r' and it was in the cloud for 't' seconds.

r ∝ t

r = kt [ k is the proportionality constant]

If r = 0.5 inches and t = 10 seconds

Then, 0.5 = k × 10

k = $\frac{0.5}{10}$

k = 0.05

Now we have to find the duration t for which hailstone was in the cloud having radius = 1.25 inches.

1.25 = 0.05 × t

t = $\frac{1.25}{0.05}$

t = 25 second

Therefore, hailstone remained in the cloud for 25 seconds.

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riadik2000 [5.3K]

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2 years ago

Read 2 more answers

Pablo generates the function f (x) = three-halves (five-halves) Superscript x minus 1 to determine the xth number in a sequence.

kondor19780726 [428]

Answer:

f(x + 1) = Five-halves f(x) (A)

Question:

The complete question as found in brainly( ID:13525864) is stated below.

Pablo generates the function f(x) = three-halves (five-halves) Superscript x minus 1 to determine the xth number in a sequence.

Which is an equivalent representation?

f(x + 1) = Five-halvesf(x)

f(x) = Five-halvesf(x + 1)

f(x + 1) = Three-halvesf(x)

f(x) = Three-halvesf(x + 1)

Step-by-step explanation:

f(x) = (3/2)(5/2)^(x-1)

Where 3/2 = three-halves and 5/2 = (five-halves)

To determine an equivalent representation, let's assign values to x to see the outcome and compare it with the options.

f(x) = (3/2)(5/2)^(x-1)

For x = 1

f(x) = (3/2)(5/2)^(1-1) = (3/2)(5/2)^(0)

f(x) =(3/2)(1) = 3/2

For x = 2

f(x) = (3/2)(5/2)^(2-1) = (3/2)(5/2)^(1)

f(x) =(3/2)(5/2)

So from the above assigned values

f(x=1) = 3/2

f(x=2) = f(x + 1) = f(1 + 1)

f(x + 1) = (3/2)(5/2)

Since f(x) = 3/2

f(x+1) = (3/2)(5/2) = f(x) × 5/2 = 5/2f(x)

From the options, an equivalent representation: f(x + 1) = Five-halves f(x)

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