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Agata [3.3K]
2 years ago
7

If a person burns 2171 Cal each day, how much energy (kJ) does she burn in 2 days??

Chemistry
1 answer:
Nataly_w [17]2 years ago
7 0

As 1 calorie = 4.184 jouls

Or

<span>1 calorie = 0.004184 kilojouls</span>

Total calories for two days = 2171 x 2 = 4342 calories

<span>Hence the energy in kj = 4342 x 0.004184 = 18.16 kj </span>

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Give the nuclide symbol for an atom that has<br> mass number 64 and 35 neutrons.
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The mass number represents the summation of the number of protons and the number of neutrons in the nucleus of an atom.
We are given that the mass number is 64 and that the number of neutrons is 35. Therefore:
number of protons = 64 - 35 = 29 protons

In ground state, number of protons in an atom is equal to the number of electrons. Therefore,
number of electrons = 29 electron

Using the periodic table, we will find that the element that has 29 electrons in ground state is copper.
The nuclide symbol of copper is shown in the attached image.

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2 years ago
A 150 W electric heater operates for 12.0 min to heat an ideal gas in a cylinder. During this time, the gas expands from 3.00 L
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<u>Answer:</u> The change in internal energy of the gas is 108.835 kJ

<u>Explanation:</u>

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where,

W = work done

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W=-(1.03)\times (11.0-3.00)=8.24L.atm=834.9J=0.835kJ     (Conversion factor:  1 L. atm = 101.325 J)

Calculating the heat from power:

Q=P\times t

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Q = heat required

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t =  time = 12 min = 720 s       (Conversion factor:  1 min = 60 s)

Putting values in above equation:

Q=150\times 720=108000J=108kJ

The equation for first law of thermodynamics follows:

Q=dU+W

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Q = total amount of heat required = 108 kJ

dU = Change in internal energy = ?

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Putting values in above equation, we get:

108kJ=dU+(-0.835)\\\\dU=(108+0.835)=108.835kJ

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Answer:

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