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drek231 [11]
2 years ago
3

A charge of +10.0 nC is placed at the center of an uncharged conducting spherical shell of inner radius 0.10 m and outer radius

0.15 m. The electric field at a distance of 0.05 m from the outside surface of the shell is closest to
Physics
1 answer:
Naddik [55]2 years ago
4 0

Answer:

Explanation:

A charge of +10.0 nC is placed at the center of an uncharged conducting spherical shell will induce a charge of - 10.0 nC on the inner surface and

+10.0 nC on the outer surface of the shell. To know electric field at a point .05 m outside shell or at .2 m from the centre of the shell , we shall consider a gaussian surface of .2 m radius and calculate the total flux passing through the surface . If E be the elctric flux required

E x 4πr² = q /ε₀ , q is total charge inside surface

total net  charge inside  q  = +10.0 nC

E   =  q /4πε₀r²

= 9 x 10⁹ x 10⁻⁸ / (0.2)²

= 2250 N/C .

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Explanation:

The given data is as follows.

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Formula to calculate the time is as follows.

          Q_{t}  = Q_{o} [e^{\frac{-t}{\tau}]

       13.5 \times 10^{-6} = 100 \times 10^{-6} [e^{\frac{-t}{2}}]

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2 years ago
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Answer:

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r = \frac{a}{\sqrt2}

r = \frac{10nm}{\sqrt2} = 7.07 nm

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now the net potential is given as

V = \frac{4 * 9*10^9 * (-1.6 * 10^{-19})}{7.07 * 10^{-9}}

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Now work done in this process is given as

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konstantin123 [22]

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