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2 years ago

Which property is characteristic of alkenes, alkynes, and aromatic hydrocarbons?

Chemistry

2 answers:

Alecsey [184]2 years ago

7 0

The best and most correct answer among the choices provided by your question is the third choice or letter C.

"Their densities are lower than the density of water." is a common property among alkenes, alkynes, and aromatic hydrocarbons.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

harina [27]2 years ago

6 0

The answer is:

C.Their densities are lower than the density of water.

The Explanation:

According to the table below of the density of alkynes you will see that it is lower than the density of water. densities of alkenes , alkynes and aromatic hydrocarbons are lower than the water.

and the alkenes are insoluble in water because it has a non polar characteristics and it is also lighter than water because its density is lower than water.

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What is the benefit of having a limiting reagent when performing a lab experiment

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Answer : The role of limiting reagent or reactant is important in a chemical reaction because it can help the chemist to predict that complete amount of reactant is consumed, as it is limiting the reaction, only required moles of products can get formed instead of the theoretical yield where the perfect amount is used.

In short, Limiting reactant in a chemical reaction is the substance that is totally consumed when the chemical reaction is found to be complete.

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2 years ago

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Compound a on ozonolysis yields acetophenone and propanal. what is the structure of compound a? 1-phenyl-1-hexene 1-phenyl-2-pen

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Answer:
2-Phenyl-2-Penetene on ozonolysis yields acetophenone and propanal.

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2 years ago

Determine ΔH for the reaction CaCO3 → CaO + CO2 given these data: 2 Ca + 2 C + 3 O2 → 2 CaCO3 ΔH = −2,414 kJ C + O2 → CO2 ΔH = −

kicyunya [14]

Answer:

The ΔH for the reaction is -456.5 KJ

Explanation:

Here we want to determine ΔH for the reaction;

Mathematically;

ΔH = ΔH(product) - ΔH(reactant)

In the case of the first reaction;

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3) ...........................(*)

From the other reactions, we can get the respective ΔH for the individual molecule in the reaction

In second reaction;

Kindly note that for elements, molecule of gases, ΔH = 0

What this means is that throughout the solution;

ΔH(Ca) = 0 KJ

ΔH(O2) = 0 KJ

ΔH(C) = 0 KJ

Thus, in writing the equation for the subsequent chemical reactions, we shall need to write and equate the overall ΔH for the reaction to that of the product alone

So in the second reaction

ΔH = 2ΔH(CaCO3)

Thus;

-2414/2 = ΔH(CaCO3)

ΔH(CaCO3) = -1,207 KJ

Moving to the third reaction, we have;

ΔH = ΔH(CO2)

Hence ΔH(CO2) = -393.5 KJ

For the last reaction;

ΔH = ΔH(CaO)

Hence ΔH(CaO) = -1270 KJ

Going back to equation *

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3)

Using the values of the ΔH of the respective molecules given above,

ΔH = -1270 + (-393.5) - (-1207)

ΔH = -456.5 KJ

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2 years ago

Starting with 1.5052g of BaCl2•2H2O and excessH2SO4, how many grams of BaSO4 can be formed?

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