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lora16 [44]
2 years ago
6

Order the bond angles of the molecules or ions from smallest to largest: O3+, O3, O3-

Chemistry
2 answers:
malfutka [58]2 years ago
8 0

The bond angles of the molecules or ions from smallest to largest:

O3- , O3 , O3+

<u>Explanation:</u>

O3- has the smallest bond angle because the added electron makes two places for electron repulsion as it allocates time on the central O.

O3 has lowering bond angle because at O3 appearance of alone pair over oxygen it will experience contracting so it may cause lowering bond angle.

O3+ has a lower electronegativity so it has a higher bond angle. Electronegativity is the tendency of an atom to attract a shared pair of the electron. so electronegativity decreases than bond angle increase so O3 has higher electronegativity so it has lowering bond angle than O3+.

oee [108]2 years ago
4 0

Answer:

O3+, O3, O3-

Explanation:

O3- has the highest bond angle because it has the highest electro negative value. Increase in electronegativity leads to increase in bond angles so as to minimize interelectronic repulsion between the electrons. Decrease in electronegativity leads to decrease in bond angle because the repulsion is minimized.

In general, the more electronegative an ion is, the larger the bond angle. The more electropositive an ion is, the smaller the bond angle. Hence cations are smaller than anions.

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Assuming ideal solution behavior, what is the freezing point of a solution of 9.04 g of I2 in 75.5 g of benzene?
cluponka [151]

Answer:

3.1°C

Explanation:

Using freezing point depression expression:

ΔT = Kf×m×i

<em>Where ΔT is change in freezing point, Kf is freezing point depression constant (5.12°c×m⁻¹), m is molality of the solution and i is Van't Hoff factor constant (1 For I₂ because doesn't dissociate in benzene).</em>

Molality of 9.04g I₂ (Molar mass: 253.8g/mol) in 75.5g of benzene (0.0755kg) is:

9.04g ₓ (1mol / 253.8g) = 0.0356mol I₂ / 0.0755kg = 0.472m

Replacing in freezing point depression formula:

ΔT = 5.12°cm⁻¹×0.472m×1

ΔT = 2.4°C

As freezing point of benzene is 5.5°C, the new freezing point of the solution is:

5.5°C - 2.4°C =

<h3>3.1°C</h3>

<em />

3 0
2 years ago
Calculate the number of kilojoules of energy required to convert 50.0 grams of solid DMSO initially at a temperature of 19.0°C t
GuDViN [60]

Answer:

20.79 kilojoules

Explanation:

Using Q = m×c×∆T

Where;

Q = Quantity of heat (J)

c = specific heat capacity of solid DMSO (1.80 J/g°C)

m = mass of DMSO

∆T = change in temperature

According to the provided information, m= 50g, initial temperature = 19.0°C, final temperature= 250.0°C

Q = m×c×∆T

Q = 50 × 1.80 × (250°C - 19°C)

Q = 90 × 231

Q = 20790 Joules

To convert Joules to kilojoules, we divide by 1000 i.e.

20790/1000

= 20.79 kilojoules

Hence, 20.79 kilojoules of energy is required to convert 50.0 grams of solid DMSO to gas.

4 0
2 years ago
A 0.0035 M aqueous solution of a particular compound has pH = 2.46. The compound is (A) a weak base (B) a weak acid (C) a strong
slava [35]

Answer:

(a) A strong acid

Explanation:

We have given the pH of the solution is 2.46

pH=2.46  

So the concentration of H^+=10^{-pH}=10^{-2.46}=0.00346

solution having H+ concentration more than H^+=10^{-7} is acidic

Since in the given solution, H+ concentration is 0.00346 M which is more than 10^{-7}[/tex] so this is an acidic solution

Note-The concentration of H^+ decide the behavior of the solution that is, it is acidic or basic

7 0
2 years ago
Which describes any compound that has at least one element from group 17?
Contact [7]
The answer is HALIDE.
6 0
2 years ago
How does the equilibrium change to counter the removal of A in this reaction? A + B ⇌ AB
atroni [7]

 To counter the removal of A  the  equilibrium  change by <u>s</u><em>hifting toward the left</em>


<em>          </em><u><em>explanation</em></u>

<u><em> </em></u>If the  reaction  is at equilibrium  and we   alter  the condition a new equilibrium  state   is created

<u><em>   </em></u>The  removal  of   A led to the shift of equilibrium  toward the left since  it led to  less  molecules  in reactant side  which favor the backward  reaction.(  equilibrium  shift to the left)

6 0
2 years ago
Read 2 more answers
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