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2 years ago

When a heavy football player and a light one run into each other, which player hits the other with

Chemistry

1 answer:

alex41 [277]2 years ago

5 0

The heavy player hits the lighter player with more force.

The lighter player gets hurt more after the collision

Explanation:

A heavy player will hit a light player with more force and eventually, the lighter player will get hurt the more after the collision.

Force is a function of mass and acceleration of a body;

Force = mass x acceleration

We can see that the more the mass and acceleration of a body, the more the force they can exert.

It is obvious that the mass of the heavier player is more than that of light player. Therefore, it exerts more force on the other one.

Also, the lighter player will get hurt the more after collision. The momentum with which the heavier football player hits the light one is very great. After the collision, the light footballer will most definitely change acceleration and direction of traveling.

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I NEED HELP ASAP, WILL MARK BRAINLEST!

Andre45 [30]

Answer:

1. 90%

2. 217.4 g O₂

3. 95.0%

4. Trial 2 ratios

Explanation:

Original: SiCl₄ + O₂ → SiO₂ + Cl₂

Balanced: SiCl₄ + O₂ → SiO₂ + 2Cl₂

Trial SiCl₄ O₂ SiO₂

1 120 g 240 g 38.2 g

2 75 g 50 g 25.2 g

Percentage yield for trial 1

We need to get actual yield (38.2 g) and theoretical yield, in grams.

Mass to moles:

molar mass SiCl₄: 28.09 + 4(35.45) = 169.9 g/mol

120 g SiCl₄ x 1 mol/169.9 g = .706 mol SiCl₄

Moles to moles:

For each mole SiCl₄, we have one mol SiO₂ based on the balanced rxn.

.706 mol SiCl₄ = .706 mol SiO₂

Moles to mass:

molar mass SiO₂: 28.09 + 2(16.00) = 60.09 g/mol

.706 mol SiO₂ x 60.09g/mol = 42.44 g SiO₂

Theoretical yield:

actual/theoretical x 100

38.2 / 42.44 = .900 = 90.0% yield

Leftover reactant for trial 1

We know oxygen is the excess reactant.

Mass to moles:

molar mass O₂ = 32.00 g/mol

240 g O₂ x 1 mol/32.00 g = 7.5 mol O₂

We used .706 mol SiO₂, so we also used .706 mol O₂.

7.5 - .706 = 6.8 moles left over

Moles to mass:

6.8 mol O₂ x 32.00g/mol = 217.4 g O₂

Percentage yield for trial 2

Mass to moles:

molar mass SiCl₄: 169.9 g/mol

75 g SiCl₄ x 1 mol/169.9 g = .441 mol SiCl₄

Moles to moles:

For each mole SiCl₄, we have one mol SiO₂ based on the balanced rxn.

.441 mol SiCl₄ = .441 mol SiO₂

Moles to mass:

molar mass SiO₂: 60.09 g/mol

.441 mol SiO₂ x 60.09g/mol = 26.5 g SiO₂

Theoretical yield:

actual/theoretical x 100

25.2 / 26.5 = .950 = 95.0% yield

Because the percentage yield of trial 2 is higher than that of trial 1, we know that the ratio of reactants in trial 2 is more efficient! We got a result closer to our theoretical yield.

6 0

2 years ago

Which statement is correct? Salts are formed by the reaction of bases with water. Most salts are ionic and are soluble in water.

Studentka2010 [4]

Salts are formed by the reaction of bases with water. - FALSE
Most salts are ionic and are soluble in water. - TRUE
Most salts are insoluble in water and lack electrical charges. - FALSE
Solutions of salt and water do not conduct electricity. - FALSE

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3 0

2 years ago

Read 2 more answers

The button batteries in small devices like watches are commonly composed of silver-zinc or mercury-zinc batteries. The reaction

photoshop1234 [79]

Answer:

The mercury button battery line notation is:

Zn⁰| Zn²|| , HgO| Hg⁰||

Explanation:

Mercury batteries either use

pure mercury(II) oxide (HgO)—which is called mercuric oxide

or a mixture of HgO with manganese dioxide (MnO2) which is as the cathode.

Anode has two half reactions:

The first step is an electrochemical reaction step:

Zn + 4OH− → Zn(OH)4−2 + 2e−[3]

cathode has a half reaction :

HgO + H2O + 2e− → Hg + 2OH−[3]

+0.0977 V standard potential is of this reaction.

which is followed by a chemical reaction step:

Anode consists of oxidation:

Zn+2OH>ZnO+H2O+2e

which gives an overall anode half-reaction of:

Zn + 2OH− → ZnO + H2O + 2e−[3]

Therefore,

The overall reaction for the battery is:

Zn + HgO → ZnO + Hg

7 0

2 years ago

Draw a triacylglycerol (triglyceride) made from glycerol, myristic acid [CH3(CH2)12COOH], palmitic acid [CH3(CH2)14COOH], and ol

Sergio039 [100]

Answer:

The triglyceride made from glycerol, myristic acid, palmitic acid and cis-oleic acid is shown in the attached pictures.

Explanation:

A triglyceride or triacylglyceride is an ester derived from glycerol and three fatty acids. The fatty acids of this exercise are myristic acid, palmitic acid and oleic acid.

A fatty acid is a biomolecule of lipid nature formed by a long linear hydrocarbon chain, of different length or number of carbon atoms, at the end of which is a carboxyl group.

The myristic acid has a carbon chain of 14 carbon atoms with a carboxyl group at one end.

Palmitic acid has a carbon chain of 16 carbon atoms with a carboxyl group at one end.

Oleic acid has a carbon chain of 18 carbon atoms with a carboxyl group at one end and a double bond at position 9.

Triglyceride is formed by the esterification of the glycerol oxidrile group and the carboxyl acid group.

7 0

2 years ago

What is the mass of a sample of NH3 containing 6.3 × 1024 molecules of NH3?

quester [9]

Answer:

178 grams

Explanation:

It is known that 1.0 mole of a compound contains Avogadro's number of molecules (6.022 x 10²³).

Using cross multiplication:

1.0 mol contains → 6.022 x 10²³ molecules.

??? mol contains → 6.3 x 10²⁴ molecules.

∴ The no. of moles of (6.3 x 10²⁴ molecules) of NH₃ = (1.0 mol)(6.3 x 10²⁴ molecules)/(6.022 x 10²³ molecules) = 10.46 mol.

∴ The no. of grams of NH₃ present = no. of moles x molar mass = (10.46 mol)(17.0 g/mol) = 177.8 g ≅ 178 g.

7 0

2 years ago