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2 years ago

When a heavy football player and a light one run into each other, which player hits the other with

Chemistry

1 answer:

alex41 [277]2 years ago

5 0

The heavy player hits the lighter player with more force.

The lighter player gets hurt more after the collision

Explanation:

A heavy player will hit a light player with more force and eventually, the lighter player will get hurt the more after the collision.

Force is a function of mass and acceleration of a body;

Force = mass x acceleration

We can see that the more the mass and acceleration of a body, the more the force they can exert.

It is obvious that the mass of the heavier player is more than that of light player. Therefore, it exerts more force on the other one.

Also, the lighter player will get hurt the more after collision. The momentum with which the heavier football player hits the light one is very great. After the collision, the light footballer will most definitely change acceleration and direction of traveling.

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Which of the following is most likely a heavier stable nucleus? (select all that apply) Select all that apply: A nucleus with a

kvv77 [185]

The question is incomplete, the complete question is;

Which of the following is most likely a heavier stable nucleus? (select all that apply) Select all that apply: A nucleus with a neutron:proton ratio of 1.05 A nucleus with a A nucleus with a neutron:proton ratio of 1.49 The nucleus of Sb-123 A nucleus with a mass of 187 and an atomic number of 75

Answer:

A nucleus with a A nucleus with a neutron:proton ratio of 1.49

A nucleus with a mass of 187 and an atomic number of 75

Explanation:

The stability of a nucleus depends on the number of neutrons and protons present in the nucleus. For many low atomic number elements, the number of protons and number of neutrons are equal. This implies that the neutron/proton ratio = 1

Elements with higher atomic number tend to be more stable if they have a slight excess of neutrons as this reduces the repulsion between protons.

Generally, the belt of stability for chemical elements lie between and N/P ratio of 1 to an N/P ratio of 1.5.

Two options selected have an N/P ratio of 1.49 hence they are heavy stable elements.

5 0

1 year ago

Suppose you perform a calorimeter experiment to determine the molar heat of neutralization of an unknown acid, H A HA, with sodi

Black_prince [1.1K]

Answer:

-86.02 kJ/ mole

Explanation:

The moles of the acid used = Molarity × Volume (L) =

= 0.50 (0.0372 L)

= 0.0186 moles

The heat released = -1.6 kJ

∴ 0.0186 moles neutralization of HA heat is: -1.6 kJ

The molar heat of neutralization due to one mole of the unknown acid = -1.6/0.0186

= -86.02 kJ/ mole

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2 years ago

What volume in<br><br> L<br><br> of a 0.724 M Nal solution contains 0.405 mol of Nal ?

Amanda [17]

Answer:

$0.5594\ \text{L}$

Explanation:

Mol of NaI = 0.405 mol

Molarity of solution = 0.724 M

Molarity is given by

$M=\dfrac{\text{mol}}{\text{Volume of solution in }NaI}\\\Rightarrow \text{Volume of solution in }NaI=\dfrac{0.405}{0.724}\\\Rightarrow \text{Volume of solution in }NaI=0.5594\ \text{L}$

The required volume is $0.5594\ \text{L}$ .

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2 years ago

The dissociation of calcium carbonate has an equilibrium constant of Kp = 1.16 at 1073 K . CaCO3(s) ⇄ CaO(s) + CO2(g) If you pla

tino4ka555 [31]

Answer:

<h3> $Pressure of CO_2 in the container=1.6 atm$ </h3>

Explanation:

First balance the chemical equation:

$CaCO_3(s)$ ⇄ $CaO(s) + CO_2(g)$

two components are solid so these two will not exert any kind of pressure in the container so at equilibrium only CO2 will apply pressure on the container

Therefore only partial pressure of CO2 will be taken for the calculation of equilibrium pressure constant i.e. Kp

$K_p=[CO_2]$