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AURORKA [14]
2 years ago
3

How many formula units are equal to 1.8 moles of magnesium iodine

Chemistry
1 answer:
Nataly [62]2 years ago
3 0

The formula units equal to 1.8 moles of magnesium iodine is 10.8396 \times 10^{23} formula units.

<u>Explanation:</u>

It is known that one mole of any compound or molecule is equal to Avogadro numbers of formula units. Basically formula unit of any compound is nothing but smallest whole number required to form a compound. As the moles is given in this question, so the number of formula units for magnesium iodine can be obtained as

1 mole of magnesium Iodine =  6.022 \times 10^{23} formula unit

Thus,

1.8 moles of magnesium Iodine =  1.8 \times 6.022 \times 10^{23}

So,

1.8 moles of magnesium Iodine =  10.8396 \times 10^{23} formula unit

Thus, the 1.8 moles of magnesium iodine will contain10.8396 \times 10^{23} formula units.

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a block of iron has a mass of 826g. what is the mass of a block of magnesium that has the same volume as the block of iron? the
fiasKO [112]

Answer is: the mass of a block of magnesium is 177.75 grams.

m(Fe) = 826 g.

d(Fe) = 7.9 g/cm³.

1) Calculate volume of iron and magnesium:

d(Fe) = m(Fe) ÷ V(Fe).

V(Fe) = m(Fe) ÷ d(Fe).

V(Fe) = 826 g ÷ 7.9 g/cm³.

V(Fe) = V(Mg) = 104.56 cm³.

2) Calculate mass of magnesium:

m(Mg) = V(Mg) · d(Mg).

m(Mg) = 104.56 g/cm³ · 1.7 g/cm³.

m(Mg) = 177.75 g.

8 0
2 years ago
the height of a column of mercury in barometer is 754.3mm. what us the atmospheric pressure in atm. in kPa.
Aleksandr-060686 [28]
1 atm = 760mmHg
754.3 mmHg / 760 mmHg * 1atm = 0.99 atm
760 mmHg = 101.3 KPa
754.3 mmHg/ 760mmHg *101.3 KPa = 100.54 KPa

Hope this helps!
8 0
2 years ago
Write an equation for the formation of bf3(g) from its elements in their standard states.
blagie [28]
In nature, boron is monoatomic. Therefore, its formula is B.
On the other hand, fluorine is diatomic. Therefore, its formula is F2

Now, the basic unbalanced equation is:
B + F2 .........> BF3

Now, we need to balance this equation. As you can see, we have two fluorine moles entering the reaction and 3 formed in the products.
Balancing the equation, we will reach the following balanced reaction:
2B + 3F2 .......> 2BF3 
7 0
2 years ago
Titration reveals that 11.6 mL of 3.0M sulfuric acid are required to neutralize the sodium hydroxide in 25.00mL of NaOH solution
Deffense [45]

Answer:

Explanation:

Molarity of acid(volume of acid)(# of H ions)= molarity of base(volume of base)(# of OH ions)

M(v)(#)=M(v)(#)

sulfuric acid    sodium hydroxide

H2SO4           NaOH

(3)(11.6)(2)=M(25)(1)

M=2.784

6 0
2 years ago
How many acidic protons are there in 0.6137 g of KHP?
andreyandreev [35.5K]

0.6137 g of KHP contains 1.086 × 10^21 acidic protons.

Number of moles of KHP = mass of KHP/molar mass of KHP

Molar mass of KHP = 204.22 g/mol

Mass of KHP = 0.6137 g

Number of moles of KHP = 0.6137 g/204.22 g/mol = 0.003 moles of KHP

Now,  1 each molecule of KHP contains 1 acidic proton.

For 0.003 moles of KHP there are; 0.003 × 1 × NA

Where NA is Avogadro's number.

So;  0.003 moles of KHP contains 0.003 × 1 × 6.02 × 10^23

= 1.086 × 10^21 acidic protons.

Learn more: brainly.com/question/16672114

7 0
2 years ago
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