forces F1 (east) and F2 are simultaneously applied to a 3.0kg mass. when F2 is east, a=5.0m/s² east and when F2 is west a=1.0m/s
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Answer:
The net torque is 0.0372 N m.
Explanation:
A rotational body with constant angular acceleration satisfies the kinematic equation:
(1)
with ω the final angular velocity, ωo the initial angular velocity, α the constant angular acceleration and Δθ the angular displacement (the revolutions the sphere does). To find the angular acceleration we solve (1) for α:
Because the sphere stops the final angular velocity is zero, it's important all quantities in the SI so 2.40 rev/s = 15.1 rad/s and 18.2 rev = 114.3 rad, then:
The negative sign indicates the sphere is slowing down as we expected.
Now with the angular acceleration we can use Newton's second law:
(2)
with ∑τ the net torque and I the moment of inertia of the sphere, for a sphere that rotates about an axle through its center its moment of inertia is:
With M the mass of the sphere an R its radius, then:
Then (2) is:
Answer:
(a) momentum of photon is 1.205 x 10⁻²⁷ kgm/s
velocity of electron is 1323.88 m/s
momentum of the electron is 1.205 x 10⁻²⁷ kgm/s
(b) momentum of photon is 1.506 x 10⁻²⁷ kgm/s
velocity of electron is 1654.85 m/s
momentum of the electron is 1.506 x 10⁻²⁷ kgm/s
(c) The momentum of the photon is equal to the momentum of the electron
Explanation:
(a)
wavelength of green light, λ = 550 nm
momentum of photon is given by;
velocity of electron is given by;
momentum of the electron is given by;
p = mv
p = (9.1 x 10⁻³¹) (1323.88)
p = 1.205 x 10⁻²⁷ kgm/s
(b)
wavelength of red light, λ = 440 nm
momentum of photon is given by;
velocity of electron is given by;
momentum of the electron is given by;
p = mv
p = (9.1 x 10⁻³¹) (1654.85)
p = 1.506 x 10⁻²⁷ kgm/s
(c) The momentum of the photon is equal to the momentum of the electron.