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Dahasolnce [82]
2 years ago
15

A block with a mass of 9.00 kg is pulled at a constant speed across a horizontal tabletop with a spring scale. The scale reads 6

1.8 N. Calculate the coefficient of kinetic friction
Physics
1 answer:
snow_tiger [21]2 years ago
7 0

Answer:0.69

Explanation:

Coefficient of kinetic friction=f/R=61.8/90=0.69

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Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air
frosja888 [35]

The frequency of the wave has not changed.

In fact, the frequency of a wave is given by:

f=\frac{v}{\lambda}

where v is the wave's speed and \lambda is the wavelength.

Applying the formula:

- In air, the frequency of the wave is:

f=\frac{400 m/s}{2 m}=200 Hz

- underwater, the frequency of the wave is:

f=\frac{1600 m/s}{8 m}=200 Hz

So, the frequency has not changed.

3 0
2 years ago
Read 2 more answers
When a mass of 25 g is attached to a certain spring, it makes 20 complete vibrations in 4.0 s. what is the spring constant of th
earnstyle [38]

Answer: The spring  of the spring is 25 N/m.

Explanation:

Mass of the body = 25 g= 0.025 kg (1 kg = 1000 g)

Oscillation is 4 sec = 20

Oscillation in 1 sec =\frac{20}{4}=5

Frequency of the vibration of the spring = 5 s^{-1}=5 Hz

Force constant can be calculated bu using the relation between the frequency and, mass and spring constant 'k'

Frequency=\frac{1}{2\pi}\times \sqrt{\frac{k}{m}}

5 s^{-1}=\frac{1}{2\times 3.14}\times \sqrt{\frac{k}{0.025 kg}}

k=24.649 N/m\approx 25 N/m

The spring  of the spring is 25 N/m.

3 0
2 years ago
Read 2 more answers
The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth. If a rock weighs 75.0 N on earth, compu
IgorLugansk [536]

Answer:

g = 0.905 gE

W  = 67.9 N

Explanation:

given data

mass of Venus mv =  81.5% = 0.815

radius Rv = 94.9% = 0.949

weighs W = 75.0 N

solution

we apply here acceleration due to gravity at earth surface that is

g = \frac{Gm}{R^2}   = 9.80 m/s²  ............1

so

g = \frac{G(0.815)}{0.949R^2}  

g = 0.905 gE

and

W = m gv

W = 0.905 m gE

W  = 0.905 × 75

W  = 67.9 N

7 0
2 years ago
A soccer ball kicked with a force of 13.5 n accelerates at 6.5 m/s^2 to the right. what is the mass of the ball?
natita [175]

Answer:

2.08 kg

Explanation:

Newton's second law states that the acceleration of an object is proportional to the force applied to the object, according to the equation:

F=ma

where F is the force applied, m is the mass of the object and a its acceleration.

In this situation, the soccer ball is kicked with a force F=13.5 N and its acceleration is a=6.5 m/s^2, therefore its mass is

m=\frac{F}{a}=\frac{13.5 N}{6.5 m/s^2}=2.08 kg

6 0
2 years ago
A person walks 25 m west and then 45 m at the angle of 60 degrees north of east what is the magnitude of the total displacement?
expeople1 [14]


To solve this question, we need to use the component method and split our displacements into their x and y vectors. We will assign north and east as the positive directions.

The first movement of 25m west is already split. x = -25m, y = 0m.

The second movement of 45m [E60N] needs to be split using trig.
x = 45cos60 = 22.5m
y = 45sin60 = 39.0m

Then, we add the two x and two y displacements to get the total displacement in each direction.

x = -25m + 22.5m = -2.5m
y = 0m + 39.0m

We can use Pythagorean theorem to find the total displacement.
d² = x² + y²
d = √(-2.5² + 39²)
d = 39.08m

And then we can use tan to find the angle.
inversetan(y/x) = angle
inversetan(39/2.5) = 86.3

Therefore, the total displacement is 39.08m [W86.3N]

8 0
2 years ago
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