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almond37 [142]
2 years ago
6

As the earth rotates, what is the speed of a physics student in Miami, Florida, at latitude 26∘26∘? Ignore the revolution of the

earth around the sun. The radius of the earth is 6400 kmkm. Express your answer with the appropriate units.
Physics
1 answer:
Ugo [173]2 years ago
7 0

Answer:

v = 418.31 m/s

Explanation:

given,

Radius of earth = 6400 Km

latitude at Miami, Florida = 26°

first we have to find the radius of the rotation at that latitude.

radius = 6400 x 1000 x cos 26°

circumference will be equal to = 2 π r

cos θ is used because at equator angle is zero radius is maximum and cos θ is maximum at 0°

calculation of time to

time = 24 hr

t = 24 x 60 x 60 = 86400 s

speed = \dfrac{distance}{time}

v= \dfrac{2\times \pi \times 6400\times 1000\times cos 26^0}{86400}

      v = 418.31 m/s

speed of a physics student in Miami, Florida is equal to v = 418.31 m/s

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A baseball catcher puts on an exhibition by catching a 0.15-kg ball dropped from a helicopter at a height of 101 m. What is the
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Explanation:

Hi there!

To solve this problem, let´s use the law of conservation of energy. Since there is no air resistance, the only energies that we should consider is the gravitational potential energy and the kinetic energy. Because of the conservation of energy, the loss of potential energy of the ball must be compensated by a gain in kinetic energy.

In this case, the potential energy is being converted into kinetic energy as the ball falls (this is only true when there are no dissipative forces, like air resistance, acting on the ball). Then, the loss of potential energy (PE) is equal to the increase in kinetic energy (KE):

We can express this mathematically as follows:

-ΔPE = ΔKE

-(final PE - initial PE) = final KE - initial KE

The equation of potential energy is the following:

PE = m · g · h

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g = acceleration due to gravity.

h = height.

The equation of kinetic energy is the following:

KE = 1/2 · m · v²

Where:

KE = kinetic energy.

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v = velocity.

Then:

-(final PE - initial PE) = final KE - initial KE          

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√(2g (hi - hf)) = v

Replacing with the given data:

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v = 44 m/s

The speed of the ball 1.0 m above the ground is 44 m/s.

3 0
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