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Temka [501]
2 years ago
7

A 4kg block is sliding on a horizontal frictionless floor at a speed of 2.5ms and runs into a horizontal spring. The spring has

a spring constant of 30Nm. What is the maximum compression of the spring after the collision?
Physics
2 answers:
alexgriva [62]2 years ago
8 0

Answer:

Explanation:

Given

mas of block m=4\ kg

speed of block v=2.5\ m/s

spring constant k=30\ N-m

As the mass collides with the spring its kinetic energy is converted to the Elastic Potential energy of the spring

\frac{1}{2}mv^2=\frac{1}{2}kx^2

x=v\sqrt{\frac{m}{k}}

x=2.5\times \sqrt{\frac{4}{30}}

x=0.912\ m

fgiga [73]2 years ago
3 0

Answer:

91 cm

Explanation:

mass, m = 4 kg

velocity, v = 2.5 m/s

spring constant, K = 30 N/m

Let the compression in spring is y.

The kinetic energy of the block is converted into elastic potential energy of the spring.

1/2 mv² = 1/2 Ky²

4 x 2.5 x 2.5 = 30 x y²

y = 0.91 m = 91 cm

Thus, the maximum compression in the spring is 91 cm.

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Amanda [17]

Answer:

Explanation:

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m = 4 / g

At the bottom of the swing let centripetal acceleration be a

T - mg = ma

9 - 4 = ma

5 = 4 a  / g

a =  5g / 4

6 0
2 years ago
This means that the speed at which the bullet travels across Earth's surface (its magnitude of horizontal velocity) does not aff
Dmitry_Shevchenko [17]

Answer: the speed at which it falls toward the Earth.


Explanation:


A bullet travelling across Earth's surface with some horizontal velocity is classical example of projectile motion.


Projectile motion is an idealization of the motion under the action of gravity neglecting the influence of the air (no drag force nor friction).


This  kind of motion is the result of two independent motions: vertical motion and horizontal motion.


The observed net velocity is the vectorial sum of the vertical and horizontal velocities.


The horizontal velocity is constant, since there is not any force acting in the horizontal axis. Thi is, the object, following the first Law of Newton (inertia law) tends to continue in uniform rectilinear movement (with zero acceleration).


The vertical velocity, this is the velocity at which the bullet falls toward the Earth, is influenced (accelerated) by the action of the gravity of the Earth. So, the vertical velocity is accelerated by the pull of the Earth.


Vertical and horizontal velocities are independent of each other, which means that the speed or the magnitude of the horizontal velocity does not affect the speed at which an object (the bullet) falls toward the Earth.

6 0
2 years ago
Water runs into a fountain, filling all the pipes, at a steady rate of 0.750 m3>s. (a) How fast will it shoot out of a hole 4
kati45 [8]

Answer:

velocity  = 472 m/s

velocity = 52.4 m/s

Explanation:

given data

steady rate = 0.750 m³/s

diameter = 4.50 cm

solution

we use here flow rate formula that is

flow rate = Area × velocity .............1

0.750 = \frac{\pi }{4} × (4.50×10^{-2})²  × velocity

solve it we get

velocity  = 472 m/s

and

when it 3 time diameter

put valuer in equation 1

0.750 = \frac{\pi }{4} × 3 ×  (4.50×10^{-2})²  × velocity

velocity = 52.4 m/s

5 0
2 years ago
What is the magnitude of the force a 1.5 x 10-3 C charge exerts on a 3.2 x 10-4 C charge located 1.5 m away?
sweet [91]
The magnitude of the force<span> a 1.5 x 10-3 C charge exerts on a 3.2 x 10-4 C charge located 1.5 m away is 1920 Newtons. The formula used to solve this problem is:

F = kq1q2/r^2

where:
F = Electric force, Newtons
k = Coulomb's constant, 9x10^9 Nm^2/C^2
q1 = point charge 1, C
q2 = point charge 2, C
r = distance between charges, meters

Using direct substitution, the force F is determined to be 1920 Newtons.</span>
7 0
2 years ago
An object travels 50 m in 4 s. It had no initial velocity and experiences constant acceleration. What is the magnitude of the ac
Allisa [31]

Answer:

The formula to calculate velocity in this case:

v = v0 + at

=> a = (v - v0)/t

       = (50 - 0)/4

       = 50/4 = 12.5 (m/s2)

Hope this helps!

:)

3 0
2 years ago
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