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Galina-37 [17]
2 years ago
12

A local bagel shop produces two products: bagels (B) and croissants (C). Each bagel requires 6 ounces of flour, 1 gram of yeast,

and 2 tablespoons of sugar. A croissant requires 3 ounces of flour, 1 gram of yeast, and 4 tablespoons of sugar. The company has 6,600 ounces of flour, 1,400 grams of yeast, and 4,800 tablespoons of sugar available for today's production run. Bagel profits are 20 cents each, and croissant profits are 30 cents each. --------------------- a) Max Profit = X _______ +Y ___________ (use cents) b) Subject to: _____X + ______Y <= ________Flour, _____X + ______Y <= ________Yeast _____X + ______Y <= 4800 Sugar X,Y >= 0

Mathematics
1 answer:
KengaRu [80]2 years ago
4 0

Answer:

  see below

Step-by-step explanation:

If we let X represent the number of bagels produced, and Y the number of croissants, then we want ...

(a)   Max Profit = 20X +30Y

(b)   Subject to ...

     6X +3Y ≤ 6600 . . . . . . available flour

     X + Y ≤ 1400 . . . . . . . . available yeast

     2X +4Y ≤ 4800 . . . . . . available sugar

_____

Production of 400 bagels and 1000 croissants will produce a maximum profit of $380.

__

In the attached graph, we have shaded the areas that are NOT part of the solution set. (X and Y less than 0 are also not part of the solution set, but are left unshaded.) This approach can sometimes make the solution space easier to understand, since it is white.

The vertex of the solution space that moves the profit function farthest from the origin is the one we are seeking. The point that does that is (X, Y) = (400, 1000).

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"Consider the probability distribution of X, where X is the number of job applications completed by a college senior through the
Citrus2011 [14]

Answer:

Option b

Step-by-step explanation:

Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.

 Expected observed Diff

x p(x) p(x)*1000  

   

0 0.002 2  

1 0.011 11 14 -3

2 0.115 115 15 100

3 0.123 123 130 -7

4 0.144 144  

5 0.189 189  

6 0.238 238  

7 0.178 178  

   

1 1000

We find that there is a large difference in 2 job application

Hence option b is right.  

4 0
1 year ago
If a certain number is increased by 5 one half of the result is three-fifths of the excess of 61 over the number find the number
PSYCHO15rus [73]

Answer:

= 391/11

Let say number = N

a certain number is increased by 5

= N + 5

,one-half of the result

= (N + 5)/2

Three -fifths of the excess of 61 over the number.

= (3/5)(61 - N)

Equating both

(N + 5)/2  = (3/5)(61 - N)

multiplying by 10 both sides

=> 5(N + 5) = 6(61 - N)

=> 5N + 25 = 366 - 6N

=> 11N = 391

=> N = 391/11

Step-by-step explanation:

8 0
2 years ago
A pizzeria will only deliver to locations within a certain distance of the pizzeria. The delivery region has an area of 36pi squ
shusha [124]

No

Step-by-step explanation:

she lives 10 miles away and the pizzeria only has a 6 mile radius.

0 0
2 years ago
A jet flies 425 km from Ottawa to Québec at rate v + 60. On the return flight, the
Marina CMI [18]

Answer:

a. \frac{- 42,500}{(v + 60)(v - 40)}

Step-by-step Explanation:

Given:

Distance Ottawa to Québec = 425 km

Initial flight rate = v + 60

Return flight rate = v - 40

t = \frac{d}{r}

Required:

Flight times difference of the initial and return flights

Solution:

=>Flight time of the initial flight:

t = \frac{d}{r}

t = \frac{425}{v + 60}

=>Flight time of the return flight:

t = \frac{425}{v - 40}

=>Difference in flight times:

\frac{425}{v + 60} - \frac{425}{v - 40}

\frac{425(v - 40) -425(v + 60)}{(v + 60)(v - 40)}

\frac{425(v) - 425(40) -425(v) -425(+60)}{(v + 60)(v - 40)}

\frac{425v - 17000 -425v - 25500}{(v + 60)(v - 40)}

\frac{425v - 425v - 17000 - 25500}{(v + 60)(v - 40)}

\frac{- 42,500}{(v + 60)(v - 40)}

3 0
2 years ago
At an intersection, the red-light times are normally distributed with a mean time of 3 minutes and a standard deviation of 0.25
denpristay [2]

Percent of red lights last between 2.5 and 3.5 minutes is 95.44% .

<u>Step-by-step explanation:</u>

Step 1: Sketch the curve.

The probability that 2.5<X<3.5 is equal to the blue area under the curve.

Step 2:

Since μ=3 and σ=0.25 we have:

P ( 2.5 < X < 3.5 ) =P ( 2.5−3 <  X−μ < 3.5−3 )

⇒ P ( (2.5−3)/0.25 < (X−μ)/σ < (3.5−3)/0.25)

Since, Z = (x−μ)/σ , (2.5−3)/0.25 = −2 and (3.5−3)/0.25 = 2 we have:

P ( 2.5<X<3.5 )=P ( −2<Z<2 )

Step 3: Use the standard normal table to conclude that:

P ( −2<Z<2 )=0.9544

Percent of red lights last between 2.5 and 3.5 minutes is 0.9544(100) = 95.44% .

3 0
2 years ago
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