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Galina-37 [17]
2 years ago
12

A local bagel shop produces two products: bagels (B) and croissants (C). Each bagel requires 6 ounces of flour, 1 gram of yeast,

and 2 tablespoons of sugar. A croissant requires 3 ounces of flour, 1 gram of yeast, and 4 tablespoons of sugar. The company has 6,600 ounces of flour, 1,400 grams of yeast, and 4,800 tablespoons of sugar available for today's production run. Bagel profits are 20 cents each, and croissant profits are 30 cents each. --------------------- a) Max Profit = X _______ +Y ___________ (use cents) b) Subject to: _____X + ______Y <= ________Flour, _____X + ______Y <= ________Yeast _____X + ______Y <= 4800 Sugar X,Y >= 0

Mathematics
1 answer:
KengaRu [80]2 years ago
4 0

Answer:

  see below

Step-by-step explanation:

If we let X represent the number of bagels produced, and Y the number of croissants, then we want ...

(a)   Max Profit = 20X +30Y

(b)   Subject to ...

     6X +3Y ≤ 6600 . . . . . . available flour

     X + Y ≤ 1400 . . . . . . . . available yeast

     2X +4Y ≤ 4800 . . . . . . available sugar

_____

Production of 400 bagels and 1000 croissants will produce a maximum profit of $380.

__

In the attached graph, we have shaded the areas that are NOT part of the solution set. (X and Y less than 0 are also not part of the solution set, but are left unshaded.) This approach can sometimes make the solution space easier to understand, since it is white.

The vertex of the solution space that moves the profit function farthest from the origin is the one we are seeking. The point that does that is (X, Y) = (400, 1000).

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Worker Efficiency An efficiency study conducted for Elektra Electronics showed that the number of Space Commander walkie-talkies
nalin [4]

Answer:

a) -2t²+12t+15    b) 25, 31   c) 26

Step-by-step explanation:

a) To find out rate, we will take derivative of the given equation

dN/dt= -2t2+12t+15

b) At 9 am , it will be 1hr since the start of morning shift so t=1

dN/dt= -2(1)²+12(1)+15

dN/dt=25

At 10 am, it will  2 hrs since the start of morining shift be so t=2

dN/dt=-2(2)²+12(2)+15

DN/dt= 31

c) N(2)-N(1)= (-(2)³+6(2)²+15(2))-(-(1)³+6(1)²+15(1))

                =(46)-(20))

                = 26

4 0
1 year ago
Decide whether the following situation is looking for the percent, the part, or the whole:The 14 compact cars sold by a dealer o
borishaifa [10]

Answer:

  whole

Step-by-step explanation:

No question is posed.

If we assume we're interested in the number of cars sold on Monday, we have ...

  part = percent × whole

  14 = 56% × whole

It would seem that we're looking for the whole.

__

14/.56 = 25 cars were sold on Monday.

6 0
2 years ago
Find the area of the polygon WXYZ with its vertices at W(–3, –2), X(–3, 5), Y(2, 5), and Z(2, –2).
ki77a [65]

Answer:

The area of the polynomial is 35 square unit.

Step-by-step explanation:

It is given that area of the polygon WXYZ with its vertices at W(–3, –2), X(–3, 5), Y(2, 5), and Z(2, –2).

From the below graph it is noticed that the given polynomial is a rectangle with length 5 and width 7.

The distance formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the above formula we get,

WX=7

XY=5

YZ=7

WZ=5

The length of opposing sides are equal.

Using the Pythagoras theorem, the length of diagonal WY and XZ are

WY=\sqrt{(WX)^2+(XY)^2}=\sqrt{7^2+5^2}=\sqrt{74}

XZ=\sqrt{(XY)^2+(YZ)^2}=\sqrt{5^2+7^2}=\sqrt{74}

Since the length of the diagonal are same, therefore the given polygon is a rectangle.

The area of a rectangle is

A=l\times w

Where l is length and w is width.

The area of given polynomial is

A=5\times 7

A=35

Therefore the area of the polynomial is 35 square unit.

6 0
1 year ago
Iliana signed up for a store credit card with no annual fee to get a discount of 12.5 percent off her entire first purchase.
ivann1987 [24]
The answer is $58.32
8 0
1 year ago
Read 2 more answers
a ball is thrown with a slingshot at a velocity of 110ft/sec at an angle of 20 degrees above the ground from a height of 4.5 ft.
satela [25.4K]

Answer:

t=2.47\ s  

Step-by-step explanation:

The equation that models the height of the ball in feet as a function of time is

h(t) = h_0 + s_0t -16t ^ 2

Where h_0 is the initial height, s_0 is the initial velocity and t is the time in seconds.

We know that the initial height is:

h_0 = 4.5\ ft

The initial speed is:

s_0 = 110sin(20\°)\\\\s_0 = 37.62\ ft/s

So the equation is:

h (t) = 4.5 + 37.62t -16t ^ 2

The ball hits the ground when when h(t) = 0

So

4.5 + 37.62t -16t ^ 2 = 0

We use the quadratic formula to solve the equation for t

For a quadratic equation of the form

at^2 +bt + c

The quadratic formula is:

t=\frac{-b\±\sqrt{b^2 -4ac}}{2a}

In this case

a= -16\\\\b=37.62\\\\c=4.5

Therefore

t=\frac{-37.62\±\sqrt{(37.62)^2 -4(-16)(4.5)}}{2(-16)}

t_1=-0.114\ s\\\\t_2=2.47\ s  

We take the positive solution.

Finally the ball takes 2.47 seconds to touch the ground

4 0
2 years ago
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