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ziro4ka [17]
2 years ago
3

What is the net force on a 10-kg solid steel sphere falling in air at terminal speed?

Physics
1 answer:
STALIN [3.7K]2 years ago
5 0

When we refer to the term terminal velocity, we will therefore understand that the velocity is constant at that point. For this, if the speed is constant, the acceleration is zero.

Taking Newton's second law as a reference, we have that the force is equivalent is the product between mass and acceleration, therefore

F= ma

Since acceleration is the change of speed in an instant of time, we have to

F =m \frac{\Delta V}{t}

However, the change in speed is zero since this is constant, so we will have to

F= (10)(0)

F = 0

Therefore the net force will be zero.

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The Americium nucleus, 241 95 Am, decays to a Neptunium nucleus, 237 93 Np, by emitting an alpha particle of mass 4.00260 u and
saveliy_v [14]

Answer:

The mass of Neptunium is 237.054 u.

Explanation:

Given that,

Mass of Americium = 241.05682 u

Mass of alpha particle = 4.00260 u

The equation is,

_{95}^{241}Am\rightarrow _{93}^{237}NP+\alpha\ particle+5.5 MeV

Let the mass of Neptunium is m.

Since the mass remain same.

We need to calculate the mass of Neptunium

Using formula of mass

Mass of Neptunium =  Mass of Americium -Mass of alpha particle

Put the value into the formula

m=241.05682 -4.00260

m=237.054\ u

Hence, The mass of Neptunium is 237.054 u.

8 0
2 years ago
Which correctly identifies the parts of a transverse wave? A: crest B: amplitude C: wavelength D: trough A: trough B: amplitude
jenyasd209 [6]

Explanation :

In transverse waves the particles are oscillating perpendicular to the direction of propagation of waves.

The uppermost part of the wave is crests and the lowermost part is troughs.

Wavelength of a transverse wave is defined as the distance between two consecutive crests or troughs.

Amplitude is the maximum distance or displacement covered by a wave.

So, crest, amplitude, trough and wavelength identifies the parts of a transverse wave.

9 0
2 years ago
Read 2 more answers
4. A 505-turn circular-loop coil with a diameter of 15.5 cm is initially aligned so that
Basile [38]

The strength of the magnetic field is 4.8\cdot 10^{-5} T

Explanation:

According to Faraday's Law, the magnitude of the induced emf in the coil is equal to the rate of changeof the flux linkage through the coil:

\epsilon = \frac{N\Delta \Phi}{\Delta t} (1)

where

N = 505 is the number of turns in the coil

\Delta \Phi is the change in magnetic flux through the coil

\Delta t = 2.77 ms = 2.77\cdot 10^{-3} s is the time interval

\epsilon = 0.166 V

The coil is rotated from a position perpendicular to the Earth's magnetic field to a position parallel to it, so the final flux is zero, and the magnitude of the flux change is simply equal to the initial flux:

\Delta \Phi = B A cos \theta

where

B is the strength of the magnetic field

A is the area of the coil

\theta=0^{\circ} is the angle between the normal to the coil and the field

The area of the coil can be written as

A=\pi r^2

where

r=\frac{15.5 cm}{2}=7.75 cm = 7.75\cdot 10^{-2} m is its radius

Substituting everything into eq.(1) and solving for B, we find:

\epsilon= \frac{NB\pi r^2 cos \theta}{\Delta t}\\B=\frac{\epsilon \Delta t}{\pi r^2 cos \theta}=\frac{(0.166)(2.77\cdot 10^{-3})}{(505)\pi (7.75\cdot 10^{-2})^2(cos 0^{\circ})}=4.8\cdot 10^{-5} T

Learn more about magnetic fields:

brainly.com/question/3874443

brainly.com/question/4240735

#LearnwithBrainly

8 0
2 years ago
Read 2 more answers
The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371
arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

q=m\times c\times (T_2-T_1)

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = 4.18J/g.K

T_1 = initial temperature of water = 293.0 K

T_2 = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

q=250g\times 4.18J/g.K\times (371.2-293.0)K

q=81719J

Now we have to calculate the enthalpy of combustion of octane.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of combustion of octane = ?

q = heat released = -81719 J

n = moles of octane = 0.015 moles

Now put all the given values in the above formula, we get:

\Delta H=\frac{-81719J}{0.015mole}

\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol

Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

5 0
2 years ago
In an experiment to illustrate the propagation of sound through fluids, identical sound sources emitting at 440 Hz are used to p
earnstyle [38]

Answer:

B. In mercury, the frequency of the wave is the same as in ethanol, but the wavelength is greater.

Explanation:

To solve this easily, we can just calculate the wavelength of the sound in Ethanol and in Mercury.

In Ethanol, the wavelength will be:

λ = c/f

λ = 1160/440

λ = 2.63 m

In Mercury, the wavelength will be:

λ = c/f

λ = 1450/440

λ = 3.3 m

The wavelength of sound is greater in Mercury than in Ethanol but the frequency is the same.

Frequency of sound is not dependent on medium, but velocity and wavelength change depending on the medium.

3 0
2 years ago
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