Question

A gram of gasoline produces 45.0 kJ of energy when burned. Gasoline has a density of 0.77 g/ml. How would you ca the amount of energy produced by burning 35. L of gasoline? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.

Answer 1

Explanation:

The given data is as follows.

        Density of gasoline = 0.77 g/ml

         Volume of gasoline = 35 L = 35000 ml     (as 1 L = 1000 ml)

As we know that density of a substance is equal to its mass divided by its volume.

Mathematically,    Density = $\frac{mass}{volume}$

Hence, calculate the mass of given gasoline as follows.

                  Density = $\frac{mass}{volume}$

                         0.77 g/ml = $\frac{mass}{35000 ml}$

                       mass = 26950 g

Also, it is given that 1 g of gasoline on combustion produces 45.0 kJ of energy.

Therefore, energy produced by 26950 g of combustion of gasoline will be as follows.

                 $45.0 \times 26950$

                  = 1212750 kJ

Thus, we can conclude that the amount of energy produced by burning 35 L of gasoline is 1212750 kJ.