Answer:
(C) T
The tension T at equilibrium will be equal to the Buoyant force.
The Buoyant force is given by:
Fb = density x acceleration due to gravity x volume displaced
The change in height doesn't affect the Buoyant force and hence the tension.
Note: The figure of question is added in the attachment
Answer: 51841.5 Watts
Explanation: Using the kinematic equation for the final velocity for a constant acceleration we have:
Vf=Vi+a*t
replacing the values the results is
a=(Vf-Vi)/t= (30.55 m/s-19.44 m/s)/5s= 2.22 m/s^2
Remenber that to convert the speed in Km/h to m/s we have to multiplier by the factor 0.277.
Finally to calculate the increment of power get the final velocity we have to use Neton second law to determine the Force applied to the car.
F=m* a=2100 Kg* 2.22 m/s^2= 4666.2 N
Then increment power to accelerate is given by:
ΔPower= Force* Δ velocity= 4666.2 N* 11,11 m/s= 51841.5 Watts
Answer:
Vectors have both magnitude and direction.
Answer:
Acceleration of the crate is 0.362 m/s^2.
Explanation:
Given:
Mass of the box, m = 40 kg
Applied force, F = 15 N
Angle at which the force is applied,
= 15°
We have to find the magnitude of the acceleration.
Let the acceleration be "a".
FBD is attached with where we can see the horizontal and vertical component of force.
⇒
and ⇒ 
⇒
⇒ 
⇒ Applying concept of forces.
⇒
⇒ 
⇒
<em> ...Newtons second law Fnet = ma</em>
⇒
⇒ Plugging the values.
⇒
<em>...f is the friction which is zero here.</em>
⇒ 
⇒ 
Magnitude of the acceleration of the crate is 0.362 m/s^2.