Answer:
a)W=8.333lbf.ft
b)W=0.0107 Btu.
Explanation:
<u>Complete question</u>
The force F required to compress a spring a distance x is given by F– F0 = kx where k is the spring constant and F0 is the preload. Determine the work required to compress a spring whose spring constant is k= 200 lbf/in a distance of one inch starting from its free length where F0 = 0 lbf. Express your answer in both lbf-ft and Btu.
Solution
Preload = F₀=0 lbf
Spring constant k= 200 lbf/in
Initial length of spring x₁=0
Final length of spring x₂= 1 in
At any point, the force during deflection of a spring is given by;
F= F₀× kx where F₀ initial force, k is spring constant and x is the deflection from original point of the spring.
Change to lbf.ft by dividing the value by 12 because 1ft=12 in
100/12 = 8.333 lbf.ft
work required to compress the spring, W=8.333lbf.ft
The work required to compress the spring in Btu will be;
1 Btu= 778 lbf.ft
?= 8.333 lbf.ft----------------cross multiply
(8.333*1)/ 778 =0.0107 Btu.
Answer:
B.) to determine that electric beams in cathode ray tubes were actually made of particles
Explanation:
This is the right answer i just took the quiz on edge.
Answer:
Expression of work done is
Work done to move the sled is given as 1.94 J
Explanation:
As we know that the formula of work done is given as
here we know that
F = 6 N
d = 0.4 m
so we will have
Answer:
Wycleff is on block 1, Lilly is on block 4, Emilia is on block 12, and Quincy is on block 17.
Explanation:
Wycleff was at block 1 and heard a low pitch sound the whole time, so the police car must have been moving away from him.
Lilly observed was in block 4 change in pitch first. So the car must have passed her first.
Emilia was at block 12 observed a Doppler effect after Lilly. So the car passed her after passing Lilly
Quincy was at block 17 so she heard a high pitch sound the whole time, so the police car must have been moving toward him.
1 in=2.54 cm=(2.54 cm)(1 m/100 cm)=0.0254 m
Therefore:
1 in=0.0254 m
1 in³=(0.0254 m)³=1.6387064 x 10⁻⁵ m³
Therefore:
8.06 in³=(8.06 in³)(1.6387064 x 10⁻⁵ m³ / 1 in³)≈1.321 x 10⁻⁴ m³.
Answer: 8.06 in³=1.321 x 10⁻⁴ m³
