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guapka [62]
2 years ago
9

Kim has a metal casting company which makes commemorative coins. She has 0.12 cubic meters of silver which she needs to make int

o 1.07e5 coins of thickness 2 mm. If she uses all of the silver, what is the diameter in centimeters of each coin
Physics
1 answer:
a_sh-v [17]2 years ago
5 0

Answer:

The coin has a diameter of 2.67 cm

Explanation:

First, we need to find the volume of each coin by dividing the total volume of silver by the number of coins. We have also to do a conversion of units in terms of centimeters as follows:

V=0.12 m^3\times (\frac{100cm}{1m})^3=12000\ cm^3\\V_c=\frac{120000\ cm^3}{1.07\times10^5}= 1.121 cm^3

Then, we define the coin as a tiny cilinder to determine its diameter. In that order we use the cilinder's volumen equation as follows:

V=\pi r^2h\\r = \sqrt \frac{V}{\pi h}= \sqrt\frac{1.121 cm^3}{\pi \times 0.2cm}=1.336 cm

Finally, we know that the diameter is twice the radius, therefore the diameter of each coin is 2.67 cm.

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As the external magnetic field decreases, an induced current flows in the coil. what is the direction of the induced magnetic fi
GrogVix [38]
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4 0
2 years ago
Medical cyclotrons need efficient sources of protons to inject into their center. In one kind of ion source, hydrogen atoms (i.e
Arlecino [84]

Answer:

The radius is r =  4.434 *10^{-5} \ m

Explanation:

From the question we are told that

    The magnetic field is  B =   90 mT =  90*10^{-3} \ T

     The electron kinetic energy is  KE  =  1.4 eV = 1.4 * (1.60*10^{-19})  =2.24*10^{-19} \ J

Generally for the collision to occur the centripetal force of the electron in it orbit is equal to the magnetic force applied  

   This is mathematically represented as

   \frac{mv^2}{r}  =  qvB

=>    r =  \frac{m* v}{q *  B}

Where  m is the mass of electron with values m  =  9.1 *10^{-31} \ kg  

             v is the escape velocity  which is mathematically represented as

                v  = \sqrt{\frac{2 * KE}{m} }

So  

       r =  \frac{m}{qB}  *  \sqrt{\frac{2 *  KE}{m} }

     apply indices

    r = \frac{\sqrt{2 * KE * m} }{qB}

substituting values

   

        r = \frac{\sqrt{2 * 2.24*10^{-19}* 9.1 *10^{-31}} }{ 1.60 *10^{-19}* 90*10^{-3}}

       r =  4.434 *10^{-5} \ m

     

6 0
1 year ago
The resistivity of a metal increases slightly with increased temperature. This can be expressed as rho=rho0[1+α(T−T0)], where T0
Readme [11.4K]

Answer:

I = ΔVA[1 - α (T₀ - T)]/Lρ₀

Explanation:

We have the following data:

ΔV = Battery Terminal Voltage

I = Current through wire

L = Length of wire

A = Cross-sectional area of wire

T = Temperature of wire, when connected across battery

T₀ = Reference temperature

ρ = Resistivity of wire at temperature T

ρ₀ = Resistivity of wire at reference temperature

α = Temperature Coefficient of Resistance

From OHM'S LAW we know that;

ΔV = IR

I = ΔV/R

but,  R = ρL/A   (For Wire)

Therefore,

I = ΔV/(ρL/A)

I = ΔVA/ρL

but,   ρ = ρ₀[1 + α (T₀ - T)]

Therefore,

I = ΔVA/Lρ₀[1 + α (T₀ - T)]

I = [ΔVA/Lρ₀] [1 + α (T₀ - T)]⁻¹

using Binomial Theorem:

(1 +x)⁻¹ = 1 - x + x² - x³ + ...

In case of [1 + α (T₀ - T)]⁻¹, x = α (T₀ - T).

Since, α generally has very low value. Thus, its higher powers can easily be neglected.

Therefore, using this Binomial Approximation, we can write:

[1 + α (T₀ - T)]⁻¹ = [1 - α (T₀ - T)]

Thus, the equation becomes:

<u>I = ΔVA[1 - α (T₀ - T)]/Lρ₀ </u>

3 0
2 years ago
A particular material has an index of refraction of 1.25. What percent of the speed of light in a vacuum is the speed of light i
beks73 [17]

Answer:

80% (Eighty percent)

Explanation:

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We can find the speed of light in the material (v) using the relationship

n = c/v, similarly

v = c/n

therefore v = 2.99792458 x 10⁸  m/s ÷ (1.25) = 239 833 966 m/s

v = 239 833 966 m/s

Therefore the percentage of the speed of light in a vacuum that is the speed of light in the material can be calculated as

(v/c) × 100 = (1/n) × 100 = (1/1.25) × 100 = 0.8 × 100 = 80%

Therefore speed of light in the material (v) is eighty percent of the speed of light in the vacuum (c)

3 0
2 years ago
Read 2 more answers
A sprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100 meter dash .
GREYUIT [131]

Answer:

a) 36 m

b) 64 m

Explanation:

Given:

v₀ = 0 m/2

v = 12 m/s

t = 6 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (12 m/s + 0 m/s) (6 s)

Δx = 36 m

The track is 100 m, so the sprinter still has to run another 64 m.

5 0
2 years ago
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